Network Saboteur DescriptionA university network is composed of N computers. System administrators gathered information on the traffic between nodes, and carefully divided the network into two subnetworks in order to minimize traffic between parts.A…

Network Saboteur Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 11122   Accepted: 5372 Description A university network is composed of N computers. System administrators gathered information on the traffic between nodes, and carefully d…

Network Saboteur POJ2531 Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 10351   Accepted: 4968 Description A university network is composed of N computers. System administrators gathered information on the traffic between nodes, and car…

Network Saboteur Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 10147 Accepted: 4849 Description A university network is composed of N computers. System administrators gathered information on the traffic between nodes, and carefully divid…

C - Network Saboteur Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%lld & %llu Description A university network is composed of N computers. System administrators gathered information on the traffic between nodes, and carefully divide…

题目: A university network is composed of N computers. System administrators gathered information on the traffic between nodes, and carefully divided the network into two subnetworks in order to minimize traffic between parts. A disgruntled computer sc…

poj2531:http://poj.org/problem?id=2531 题意:给你一个图,图中点之间会有边权,现在问题是把图分成两部分,使得两部分之间边权之和最大.题解:随机算法 #include<iostream> #include<cstring> #include<cstdio> #include<algorithm> using namespace std; int n; ][]; ]; ;//时间限制是2000 int main(){ sca…

poj2531:http://poj.org/problem?id=2531 题意:给你一个图,图中点之间会有边权,现在问题是把图分成两部分,使得两部分之间边权之和最大.题解:一开始比知道怎么办,想用搜索,但是20的范围,觉得范围有点大,所以没敢打,最后还是试了试结果竟然过了. #include<iostream> #include<cstring> #include<cstdio> #include<algorithm> using namespace s…

个人心得:对于深搜的使用还是不到位,对于递归的含义还是不太清楚!本来想着用深搜构成一个排列,然后从一到n分割成俩个数组,然后后面发现根本实现不了,思路太混乱.后来借鉴了网上的思想,发现用数组来标志,当值等于一时就属于A数组,等于0时属于B数组,这样就可以构成递归,即下一个数只有在A数组和不在A数组,发现这个思想真的挺好的. DFS心得:若从第二步开始,动作变得程序化,像地图,只有上下左右,这个是只有为0不为0是就可以用深搜递归思想解决. A university network is compo…

Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 12886   Accepted: 6187 Description A university network is composed of N computers. System administrators gathered information on the traffic between nodes, and carefully divided the networ…