The Employee table holds all employees. Every employee has an Id, and there is also a column for the department Id. +----+-------+--------+--------------+ | Id | Name | Salary | DepartmentId | +----+-------+--------+--------------+ | 1 | Joe | 70000…

The Employee table holds all employees. Every employee has an Id, and there is also a column for the department Id. +----+-------+--------+--------------+ | Id | Name | Salary | DepartmentId | +----+-------+--------+--------------+ | 1 | Joe | 85000…

SQL 架构 Create table If Not Exists Employee (Id ), Salary int, DepartmentId int) Create table If Not Exists Department (Id )) Truncate table Employee insert into Employee (Id, Name, Salary, DepartmentId) values (') insert into Employee (Id, Name, Sala…

The Employee table holds all employees. Every employee has an Id, and there is also a column for the department Id. +----+-------+--------+--------------+ | Id | Name | Salary | DepartmentId | +----+-------+--------+--------------+ | 1 | Joe | 70000…

The Employee table holds all employees. Every employee has an Id, and there is also a column for the department Id. +----+-------+--------+--------------+ | Id | Name | Salary | DepartmentId | +----+-------+--------+--------------+ | 1 | Joe | 70000…

The Employee table holds all employees. Every employee has an Id, and there is also a column for the department Id. +----+-------+--------+--------------+ | Id | Name | Salary | DepartmentId | +----+-------+--------+--------------+ | 1 | Joe | 70000…

The Employee table holds all employees. Every employee has an Id, and there is also a column for the department Id. +----+-------+--------+--------------+ | Id | Name | Salary | DepartmentId | +----+-------+--------+--------------+ | 1 | Joe | 70000…

Given a non-empty array of integers, return the k most frequent elements. Example 1: Input: nums = [1,1,1,2,2,3], k = 2 Output: [1,2] Example 2: Input: nums = [1], k = 1 Output: [1] Note: You may assume k is always valid, 1 ≤ k ≤ number of unique ele…

Employee表存储员工姓名.员工所在公寓.员工工资 Department表存储公寓id 评选出各个公寓的工资前三名的员工. 遇到的问题如下: limit,in等语句不能用在嵌套select语句中,多封装一层就可以了 select子句如何访问外部的关系表,虽然可以直接访问外面第一层的,但是无法访问外面第二层的 select dep.name as Department, who.name as Employee, who.salary as Salary from department as…

问题描述 解决方案 select b.name Department,a.name Employee,a.salary Salary from Employee a,Department b where a.departmentid=b.id and (select count(distinct salary) from Employee where departmentid=a.departmentid and salary>a.salary )<3 order by departmenti…