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Description There are N beads which of the same shape and size, but with different weights. N is an odd number and the beads are labeled as 1, 2, ..., N. Your task is to find the bead whose weight is median (the ((N+1)/2)th among all beads). The foll…
Median Weight Bead Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 3162 Accepted: 1630 Description There are N beads which of the same shape and size, but with different weights. N is an odd number and the beads are labeled as 1, 2, -, N.…
#include<stdio.h> #include<string.h> #define N 100 int map[N][N]; int main() { int t,n,m,i,j,k,sum1,sum2,total,mid,a,b; scanf("%d",&t); while(t--) { scanf("%d%d",&n,&m); memset(map,0,sizeof(map)); while(m--) { s…
Median Time Limit: 1 Second Memory Limit: 65536 KB Recall the definition of the median of elements where is odd: sort these elements and the median is the -th largest element. In this problem, the exact value of each element is not given, but relatio…
POJ题目分类 | POJ题目分类 | HDU题目分类 | ZOJ题目分类 | SOJ题目分类 | HOJ题目分类 | FOJ题目分类 | 模拟题: POJ1006 POJ1008 POJ1013 POJ1016 POJ1017 POJ1169 POJ1298 POJ1326 POJ1350 POJ1363 POJ1676 POJ1786 POJ1791 POJ1835 POJ1970 POJ2317 POJ2325 POJ2390 POJ1012 POJ1082 POJ1099 POJ1114…