LeetCode——Single Number II】的更多相关文章

Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 这道题是之前那道 Single Number 单独的数字的延伸,那道题的解法…
问题: Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?   Single Number I 升级版,一个数组中其它数出现了…
题目地址:here 题目大意:一个整数数组中,只有一个数出现一次,其余数都出现3次,在O(n)时间,O(1)空间内找到这个出现一次的数 对于”只有一个数出现一次,其余数出现2次“的情况,很简单,只要把数组中所有数异或的结果就是这个出现一次的数,leetcode上也有这个题目. 关于本题:我们用一个大小为32的数组cnt来记录:(int数据的每个二进制位1的出现次数)%3,程序中cnt[i]记录第i+1个二进制位.如果某个数出现了三次并且他的第i个二进制位为1,因为做了模3操作,那么该数对数组cn…
原题地址:http://oj.leetcode.com/problems/single-number-ii/ 题意:Given an array of integers, every element appears three times except for one. Find that single one. 要求:和single number一样,线性时间复杂度,不能使用额外空间. 解题思路:这道题就比较难了.也是考察位操作.网上的位操作解法看了好半天也没有得其精髓.由于序列中除了那唯一的…
Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 题意:给定数组,除一个数仅出现一次外,其余都出现三次,找到仅出现一次的数字…
Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? Hide Tags Bit Manipulation   数组中的数均出现3…
还记得<剑指offer>和<编程之美>等书上多次出现的找一个数组中仅仅出现一次的数那个题吗? leetcode也有这道题 链接here  相信大家都知道用异或在O(n)的时间复杂度内求出的方法,这里不再赘述. 以下就是上题的升级版 Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should…
题目:Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 思路:一个比较好的方法是从位运算来考虑.每一位是0或1,由于除了一个数…
Description: Given an array of integers, every element appears three times except for one. Find that single one. 只有一个出现一次的数字,其他的都出现了3次,找出出现一次的那个数字. public class Solution { public int singleNumber(int[] nums) { Map<Integer, Integer> map = new HashMap…
题目描述: 给定一个包含n个整数的数组,除了一个数出现一次外所有的整数均出现三次,找出这个只出现一次的整数. 题目来源: http://oj.leetcode.com/problems/single-number-ii/ 题目分析: 对于除出现一次之外的所有的整数,其二进制表示中每一位1出现的次数是3的整数倍,将所有这些1清零,剩下的就是最终的数. 用ones记录到当前计算的变量为止,二进制1出现“1次”(mod 3 之后的 1)的数位.用twos记录到当前计算的变量为止,二进制1出现“2次”(…