HDU 1241 题目大意:给定一块油田,求其连通块的数目.上下左右斜对角相邻的@属于同一个连通块. 解题思路:对每一个@进行dfs遍历并标记访问状态,一次dfs可以访问一个连通块,最后统计数量. /* HDU 1241 Oil Deposits --- 入门DFS */ #include <cstdio> int m, n; //n行m列 ][]; /* 将和i,j同处于一个连通块的字符标记出来 */ void dfs(int i, int j){ || j < || i >=…

HDU 1241  Oil Deposits L -DFS Time Limit:1000MS     Memory Limit:10000KB     64bit IO Format:%I64d & %I64u   Description The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large r…

HDOJ(HDU).1241 Oil Deposits(DFS) [从零开始DFS(5)] 点我挑战题目 从零开始DFS HDOJ.1342 Lotto [从零开始DFS(0)] - DFS思想与框架/双重DFS HDOJ.1010 Tempter of the Bone [从零开始DFS(1)] -DFS四向搜索/奇偶剪枝 HDOJ(HDU).1015 Safecracker [从零开始DFS(2)] -DFS四向搜索变种 HDOJ(HDU).1016 Prime Ring Problem (…

题目传送门 /* DFS:油田问题,一道经典的DFS求连通块.当初的难题,现在看上去不过如此啊 */ /************************************************ Author :Running_Time Created Time :2015-8-4 10:11:11 File Name :HDOJ_1241.cpp ************************************************/ #include <cstdio> #i…

Oil Deposits HDU - 1241 The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous squar…

HDU 1241 是深搜算法的入门题目,递归实现. 原题目传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1241 代码仅供参考,c++实现: #include <iostream> using namespace std; ][]; int p,q; void dfs(int x,int y){ land[x][y] = '*'; ][y]!= ][y] != ] != ] != ][y+]!= ][y-] != ][y-] != ][y+] !…

HDU 1241 Oil Deposits(石油储藏) 00 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)   Problem Description - 题目描述 The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large…

HDOJ(HDU).1015 Safecracker [从零开始DFS(2)] 从零开始DFS HDOJ.1342 Lotto [从零开始DFS(0)] - DFS思想与框架/双重DFS HDOJ.1010 Tempter of the Bone [从零开始DFS(1)] -DFS四向搜索/奇偶剪枝 HDOJ(HDU).1015 Safecracker [从零开始DFS(2)] -DFS四向搜索变种 HDOJ(HDU).1016 Prime Ring Problem (DFS) [从零开始DFS…

HDU.5692 Snacks ( DFS序 线段树维护最大值 ) 题意分析 给出一颗树,节点标号为0-n,每个节点有一定权值,并且规定0号为根节点.有两种操作:操作一为询问,给出一个节点x,求从0号节点开始到x节点,所能经过的路径的权值最大为多少:操作二为修改,给出一个节点x和值val,将x的权值改为val. 可以看出是树上修改问题.考虑的解题方式有DFS序+线段树,树链剖分,CXTree.由于后两种目前还不会,选择用DFS序来解决. 首先对树求DFS序,在求解过程当中,顺便求解树上前缀和(p…

Input The input file contains one or more grids. Each grid begins with a line containing m and n, the number of rows and columns in the grid, separated by a single space. If m = 0 it signals the end of the input; otherwise 1 <= m <= 100 and 1 <=…