[Codeforces558E]A Simple Task 线段树】的更多相关文章

链接 题意:给定一个长度不超过 \(10^5\) 的字符串(小写英文字母),和不超过5000个操作. 每个操作 L R K 表示给区间[L,R]的字符串排序,K=1为升序,K=0为降序. 最后输出最终的字符串. 题解 发现只有小写英文字母,26个,直接建26棵线段树,排序的时候,直接统计每个字母的个数暴力安排即可 好像见过值域 \(10^9\) 的,不过不知道在哪了,先留个坑,等看到了或者记起来了再补 #include<bits/stdc++.h> #define REP(i,a,b) for…
E. A Simple Task 题目连接: http://www.codeforces.com/contest/558/problem/E Description This task is very simple. Given a string S of length n and q queries each query is on the format i j k which means sort the substring consisting of the characters from…
题目链接: http://codeforces.com/problemset/problem/558/E E. A Simple Task time limit per test5 secondsmemory limit per test512 megabytes 问题描述 This task is very simple. Given a string S of length n and q queries each query is on the format i j k which mea…
This task is very simple. Given a string S of length n and q queries each query is on the format i j k which means sort the substring consisting of the characters from i to j in non-decreasing order if k = 1 or in non-increasing order if k = 0. Outpu…
E. A Simple Task time limit per test5 seconds memory limit per test512 megabytes inputstandard input outputstandard output This task is very simple. Given a string S of length n and q queries each query is on the format i j k which means sort the sub…
题目链接:http://codeforces.com/contest/558/problem/E 题意:有一串字符串,有两个操作:1操作是将l到r的字符串升序排序,0操作是降序排序. 题解:建立26棵线段树,类似计数排序思想. #include <bits/stdc++.h> using namespace std; ; struct SegTree { ], sum[], l, r; }T[N << ]; ][N]; void pushup(int p, int c) { T[p…
题目链接:http://codeforces.com/problemset/problem/558/E 给一个字符串,每次对一个区间内的子串进行升序或者降序的排列,问最后字符串什么样子. 对于字符串排序,计数排序是比一般的排序要快的,但是仍然不能解决本问题. 建立26个线段树,用于统计某个字符在某个区间的情况. 那么如果对[L,R]排序,则先统计所有字符在其中的情况,并且清空该区间,根据每个字符的数量,从a到z去填充应该在的小区间. #include <iostream> #include &…
这道题好猥琐啊啊啊啊啊啊 写了一个上午啊啊啊啊 没有在update里写pushup啊啊啊啊 题目大意: 给你一个字符串s,有q个操作 l r 1 :把sl..rsl..r按升序排序 l r 0 :把sl..rsl..r按降序排序 Solution: 我们考虑建26棵线段树,第i棵线段树的[x,y]表示在[x,y]中一共有多少个字母'a'+i-1 至于修改时我们可以以升序为例,从a至z按顺序往前丢,记得要清空区间 同理,降序反过来就是了 Code: 我们可以用sort啊啊,只不过会TLE #pra…
题目链接 题意较为简单. 思路: 由于仅仅有26个字母,所以用26棵线段树维护就好了,比較easy. #include <iostream> #include <string> #include <vector> #include <cstring> #include <cstdio> #include <map> #include <queue> #include <algorithm> #include &…
题目 Source http://codeforces.com/problemset/problem/558/E Description This task is very simple. Given a string S of length n and q queries each query is on the format i j k which means sort the substring consisting of the characters from i to j in non…