poj3087 Shuffle'm Up(bfs)】的更多相关文章

http://poj.org/problem?id=3087 注意复制字符串的时候,要在末尾加上'\0',否则导致strcmp出错. 还有就是开数组大小的时候看清楚一点,别开错了debug了好久. #include<iostream> #include<cstdio> #include<queue> #include<cstring> #include<algorithm> #include<cmath> #include<se…
http://poj.org/problem?id=3087 Description A common pastime for poker players at a poker table is to shuffle stacks of chips. Shuffling chips is performed by starting with two stacks of poker chips, S1 and S2, each stack containing C chips. Each stac…
题目链接:Shuffle'm Up 除了英文题有点恶心.发现模拟 + bfs 就可以过的时候,就是水了. 一个bug 就是filp函数得到string s12失败了.恩.据大腿告知,string 并不指定字符串的初始化长度是0,也就是说我每个元素的赋值是没有意义的.或者.string 是引用型数据类型,所以名字是一个指针吧.然后str.resize()函数愉快的解决了这个问题. 还有就是对题意.字符串从左到右是从下到上.我是懵了一下的. 题意思路见代码吧. /* 题目很长.也没有看.百度到题意.…
Shuffle'm Up Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 10766   Accepted: 4976 Description A common pastime for poker players at a poker table is to shuffle stacks of chips. Shuffling chips is performed by starting with two stacks o…
Description A common pastime for poker players at a poker table is to shuffle stacks of chips. Shuffling chips is performed by starting with two stacks of poker chips, S1 and S2, each stack containing C chips. Each stack may contain chips of several…
题目链接:http://poj.org/problem?id=3087 Shuffle'm Up Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 12305   Accepted: 5708 Description A common pastime for poker players at a poker table is to shuffle stacks of chips. Shuffling chips is per…
Description A common pastime for poker players at a poker table is to shuffle stacks of chips. Shuffling chips is performed by starting with two stacks of poker chips, S1 and S2, each stack containing C chips. Each stack may contain chips of several…
题意:就是给你两副扑克,然后一张盖一张洗牌,不断重复这个过程,看能不能达到目标的扑克顺序 分析:然后就模拟下,-1的情况就是有循环节 #include<cstdio> #include<algorithm> #include<iostream> #include<cstring> #include<cmath> #include<map> #include<queue> #include<stdlib.h> #…
题目链接. AC代码如下; #include <iostream> #include <cstdio> #include <cstring> #include <cstdlib> #include <string> #include <queue> #include <algorithm> #include <map> #include <ctype.h> #include <set>…
题目: 现有字符串s1.s2.s12,其中s1.s2的长度为len,s12的长度为2*len. 是否可以通过一些操作使s1和s2转换合并成s12? 变换的操作规则如下: 假设s1=11111,s2=00000 变换后的序列 s=0101010101 假设s1=12345,s2=67890 变换后的序列 s=6172839405 如果s和s12完全相同,那么输出变换次数 如果不完全相等,s的前半部分作为s1,后半部分作为s2,重复上述过程 输入: 第一行T(1≤T≤1000),代表有T组数据. 每…