B. Bear and Friendship Condition time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Bear Limak examines a social network. Its main functionality is that two members can become friends (then th…

B. Bear and Friendship Condition time limit per test:1 second memory limit per test:256 megabytes input:standard input output:standard output Bear Limak examines a social network. Its main functionality is that two members can become friends (then th…

B. Bear and Friendship Condition time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Bear Limak examines a social network. Its main functionality is that two members can become friends (then th…

B. Bear and Friendship Condition 题目连接: http://codeforces.com/contest/791/problem/B Description Bear Limak examines a social network. Its main functionality is that two members can become friends (then they can talk with each other and share funny pic…

B. Bear and Friendship Condition time limit per test:1 second memory limit per test:256 megabytes input:standard input output:standard output Bear Limak examines a social network. Its main functionality is that two members can become friends (then th…

Bear Limak examines a social network. Its main functionality is that two members can become friends (then they can talk with each other and share funny pictures). There are n members, numbered 1 through n. m pairs of members are friends. Of course, a…

题意:如果1认识2,2认识3,必须要求有:1认识3.如果满足上述条件,输出YES,否则输出NO. 思路:显然如果是一个完全图就输出YES,否则就输出NO,如果是无向完全图则一定有我们可以用dfs来书边和点 n个节点的有向完全图边数为e=n*(n-1) 代码: #include <bits/stdc++.h> #define maxn 150000 #define ll long long using namespace std; vector <]; ]; int t; void dfs…

题目大意:给定一张无向图,要求如果 A 与 B 之间有边,B 与 C 之间有边,那么 A 与 C 之间也需要有边.问这张图是否满足要求. 题解:根据以上性质,即:A 与 B 有关系,B 与 C 有关系,那么 A 和 C 也要有关系,因此可以采用并查集加以维护,维护关系的同时顺便维护各个联通块的大小,若符合题目要求,则同一个联通块中的点必须均有关系.因此,最后计算一下每个联通块的应有关系数和最初所给的关系数比较,相等则符合,反之,不符合. 代码如下 #include <bits/stdc++.h>…

[题目链接]:http://codeforces.com/contest/791/problem/B [题意] 给你m对朋友关系; 如果x-y是朋友,y-z是朋友 要求x-z也是朋友. 问你所给的图是否符合 [题解] 用并查集处理出每个朋友"团"的大小->就是连通块 然后这个连通块里面应该要有x*(x-1)/2条边; 按照这个规则,求出应该有的边数; 然后和所给的m对比; 相同则YES,否则NO [完整代码] #include <bits/stdc++.h> usin…

Bear and Friendship Condition time limit per test 1 secondmemory limit per test 256 megabytesinput standard inputoutput standard output Bear Limak examines a social network. Its main functionality is that two members can become friends (then they can…

B. Bear and Friendship Condition time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Bear Limak examines a social network. Its main functionality is that two members can become friends (then th…

C. Bear and Different Names time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output In the army, it isn't easy to form a group of soldiers that will be effective on the battlefield. The communicati…

和FallDream组队瞎打一通--B两个人写的都挂了233,最后只剩下FallDream写的A和我写的C,最后我yy了个E靠谱做法结果打挂了,结束之后改了改就A了,难受. AC:AC Rank:180 Rating:2133-8->2125 A.Bear and Friendship Condition 题目大意:问一个无向图是否满足若a到b有边且b到c有边则a到c有边.(n<=150,000) 思路:判定每个连通块是不是团,不是则不满足,复杂度O(n). #include<cstdi…

A. Bear and Big Brother time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob. Right now, Limak…

Bear and Big Brother 签到题,直接模拟就可以了. Bear and Friendship Condition 满足只能是每个朋友圈中每个人和其他人都是朋友,这样的边数的确定的. 然后并查集求每个朋友圈大小再判断是否合法就可以啦. #include<cstring> #include<cstdio> #include<cmath> #include<algorithm> #define LL long long #define maxn 3…

Codeforces Round #405 (rated, Div. 2, based on VK Cup 2017 Round 1) 全场题解 菜鸡只会A+B+C,呈上题解: A. Bear and Big Brother 题意:我也没看太清,就是给你两个10以内的数a,b.a每天乘以3,b每天乘以2,求多少天后a大于b. 思路:应该是有公式的,不过看到数据这么小直接暴力乘求解.官方题解貌似就是这样,数据小就是水题. const int N=1e3+10; int main() { int a…

Above all, it was in the Roman time, and by means of Roman ships, that the Christian Religion was first brought into Britain, and its people first taught the great lesson that, to be good in the sight of God, they must love their neighbours as themse…

                                      B. Bear and Three Musketeers                                                                             time limit per test  2 seconds                                                                            …

D. Bear and Two Paths time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Bearland has n cities, numbered 1 through n. Cities are connected via bidirectional roads. Each road connects two dist…

D. Bear and Two Paths time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Bearland has n cities, numbered 1 through n. Cities are connected via bidirectional roads. Each road connects two dist…

D. Bear and Two Paths 题目连接: http://www.codeforces.com/contest/673/problem/D Description Bearland has n cities, numbered 1 through n. Cities are connected via bidirectional roads. Each road connects two distinct cities. No two roads connect the same p…

B. Bear and Displayed Friends 题目连接: http://www.codeforces.com/contest/658/problem/B Description Limak is a little polar bear. He loves connecting with other bears via social networks. He has n friends and his relation with the i-th of them is describ…

一种巧妙到暴力方式,这题到抽象化:在一个无向图中,找一个度数和最小到三阶到圈. 首先对边进行枚举,这样确定了两个顶点,然后在对点进行枚举,找到一个可以构成三元圈到点,则计算他们到度数和. 最后保存最小到度数和到三元圈即可.   Bear and Three Musketeers Time Limit:2000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u Submit Status Description Do you…

题目链接: B. Bear and Displayed Friends time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Limak is a little polar bear. He loves connecting with other bears via social networks. He has n friends…

题目链接: D. Bear and Two Paths time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Bearland has n cities, numbered 1 through n. Cities are connected via bidirectional roads. Each road connects tw…

一.Condition 类 在前面我们学习与synchronized锁配合的线程等待(Object.wait)与线程通知(Object.notify),那么对于JDK1.5 的 java.util.concurrent.locks.ReentrantLock 锁,JDK也为我们提供了与此功能相应的类java.util.concurrent.locks.Condition.Condition与重入锁是通过lock.newCondition()方法产生一个与当前重入锁绑定的Condtion实例,我们…

ICP技术是在MySQL5.6中引入的一种索引优化技术.它能减少在使用 二级索引 过滤where条件时的回表次数 和 减少MySQL server层和引擎层的交互次数.在索引组织表中,使用二级索引进行回表的代价相比堆表中是要高一些的.相关文档地址:http://dev.mysql.com/doc/refman/5.6/en/index-condition-pushdown-optimization.html Index Condition Pushdown optimization is use…

调用同步锁的wait().notify().notifyAll()进行线程通信 看这个经典的存取款问题,要求两个线程存款,两个线程取款,账户里有余额的时候只能取款,没余额的时候只能存款,存取款金额相同.相当于存取款交替进行,金额相同. 线程间通信,需要通过同一个同步监视器(也就是this或者显式的Object对象)调用通信方法, Object有三个方法,可以用于线程间通信 wait() 当前线程等待,并释放同步锁 wait():无限期等待 wait(long timeout):等待timeout…

转自http://blog.itpub.net/22664653/viewspace-1210844/  [MySQL]性能优化之 Index Condition Pushdown2014-07-06 21:25:57 分类: MySQL 一 概念介绍    Index Condition Pushdown (ICP)是MySQL 5.6 版本中的新特性,是一种在存储引擎层使用索引过滤数据的一种优化方式.a 当关闭ICP时,index 仅仅是data access 的一种访问方式,存储引擎通过索…

Friendship Time Limit: 2000MS   Memory Limit: 20000K Total Submissions: 10626   Accepted: 2949 Description In modern society, each person has his own friends. Since all the people are very busy, they communicate with each other only by phone. You can…