Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [9,4] Note: Each element in the result must be unique. The…

Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. 这道题让我们找两个数组相同的部分,难度不算大,我们可以用个set把nums1都…

给定两个数组,写一个函数来计算它们的交集.例子: 给定 num1= [1, 2, 2, 1], nums2 = [2, 2], 返回 [2].提示:    每个在结果中的元素必定是唯一的.    我们可以不考虑输出结果的顺序.详见:https://leetcode.com/problems/intersection-of-two-arrays/description/C++: class Solution { public: vector<int> intersection(vector<…

Given two arrays, write a function to compute their intersection.Notice Each element in the result must be unique.    The result can be in any order. Have you met this question in a real interview?Example Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], r…

这两道题都是求两个数组之间的重复元素,因此把它们放在一起. 原题地址: 349 Intersection of Two Arrays :https://leetcode.com/problems/intersection-of-two-arrays/description/ 350 Intersection of Two Arrays II:https://leetcode.com/problems/intersection-of-two-arrays-ii/description/ 题目&&am…

Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. Subscribe to see which companies asked…

题目要求 Given two arrays, write a function to compute their intersection. 题目分析及思路 给定两个数组,要求得到它们之中共同拥有的元素列表(列表中元素是唯一的).可以将所给数组转成集合,利用集合的交集的概念,最后将结果转成列表即可. python代码 class Solution: def intersection(self, nums1: List[int], nums2: List[int]) -> List[int]: n…

Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. 题目标签:Hash Table 题目给了我们两个 array, 让我们找到在两…

Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. 思路:利用 C++ 中的set 容器.…

Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [9,4] 思路 代码 class Solution { public int[] intersection(int…

Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2,2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [4,9] Note: Each element in the result should appear as…

283. Move Zeroes var moveZeroes = function(nums) { var num1=0,num2=1; while(num1!=num2){ nums.forEach(function(x,y){ if(x===0){ nums.splice(y,1); nums.push(0); } num1 = nums ; }); nums.forEach(function(x,y){ if(x===0){ nums.splice(y,1); nums.push(0);…

最近,在用解决LeetCode问题的时候,做了349: Intersection of Two Arrays这个问题,就是求两个列表的交集.我这种弱鸡,第一种想法是把问题解决,而不是分析复杂度,于是写出了如下代码: class Solution(object): def intersection(self, nums1, nums2): """ :type nums1: List[int] :type nums2: List[int] :rtype: List[int] &q…

Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in any ord…

Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2,2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [4,9] Note: Each element in the result should appear as…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:Java解法,HashSet 方法二:Python解法,set 日期 [LeetCode] 题目地址:https://leetcode.com/problems/intersection-of-two-arrays/ Difficulty: Easy 题目描述 Given two arrays, write a function to com…

Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. 我们可以使用两个指针来做,先给两个数组排序,然后用两个指针分别指向两个数组的…

There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). 这道题让我们求两个有序数组的中位数,而且限制了时间复杂度为O(log (m+n)),看到这个时间复杂度,自然而然的想到了应该使用二分查找法来求解.但是这道题…

Given two arrays, write a function to compute their intersection.Notice Each element in the result should appear as many times as it shows in both arrays.    The result can be in any order. Example Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return […

题目来源:https://leetcode.com/problems/median-of-two-sorted-arrays/ There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). 解题思路: 题目是这样的:给…

350. Intersection of Two Arrays II Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both…

Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. 给出两个数组,求他们的交集.出题的意图何在? public int[] int…

找两个数组的交集(不要多想,考虑啥序列之类的,就是简单的两堆数求交集啊!!!最后去个重就好了) //LeetCode里用到很多现成函数的时候,苦手だな- //这个题的思路是,先sort,把两个vector进行排序 //然后同时遍历两个字符串,找到相等的数字就放在结果vector里 //最后unique,求vector里独一无二的数字 //erase,得到没有重复的结果 class Solution { public: vector<int> intersection(vector<int…

查找问题 查找有无(只有键) 元素'a'是否存在 set(集合) 查找对应关系(键值对应) 元素'a'出现了几次 map(字典) set和map的底层实现是红黑树 常见操作 insert() find() erase() change(map):改变某个键对应的值 要求 给定两个数组nums,求两个数组的公共元素 输出结果中每个元素唯一 不考虑输出结果的顺序 举例 nums1=[1,2,2,1] nums2=[2,2] 结果:[2] 实现 将公共元素放入公共的set中 1 class Solut…

Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in any ord…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the…

Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [9,4] Note: Each element in the result must be unique. The…

Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in any ord…

不重复的: 方法一 ［一句话思路］:排序之后用归并. ［一刷］: 根据返回方法的类型来判断corner case.判断空.0数组的corner case还不一样,得分开写 由于先排序了,nums1[i] < nums2[j]时,i++可以继续在nums2[j]里找是否有相同的 index=0时肯定不会重复,一定要插入 写法是Arrays.sort(nums1) 定义int i还不够,要初始化为0 并列用几个if可能会越界,还是用else if吧 result定义的长度不能是temp.length…

Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. 代码如下: public class Solution { public in…