Given a nested list of integers, implement an iterator to flatten it. Each element is either an integer, or a list -- whose elements may also be integers or other lists. Example 1: Given the list [[1,1],2,[1,1]], By calling next repeatedly until hasN…

Implement an iterator to flatten a 2d vector. For example,Given 2d vector = [ [1,2], [3], [4,5,6] ] By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,2,3,4,5,6]. Hint: How many variables do y…

Given a binary tree, flatten it to a linked list in-place. For example,Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 click to show hints. Hints: If you notice carefully in the flattened tree, each node's right…

Why underscore (觉得这一段眼熟的童鞋可以直接跳到正文了...) 最近开始看 underscore.js 源码,并将 underscore.js 源码解读 放在了我的 2016 计划中. 阅读一些著名框架类库的源码,就好像和一个个大师对话,你会学到很多.为什么是 underscore?最主要的原因是 underscore 简短精悍(约 1.5k 行),封装了 100 多个有用的方法,耦合度低,非常适合逐个方法阅读,适合楼主这样的 JavaScript 初学者.从中,你不仅可以学到用…

Given a binary tree, flatten it to a linked list in-place. For example,Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 click to show hints. Hints: If you notice carefully in the flattened tree, each node's right…

题目要求: (**) Flatten a nested list structure. Example: scala> flatten(List(List(1, 1), 2, List(3, List(5, 8)))) res0: List[Any] = List(1, 1, 2, 3, 5, 8) 参考:http://blog.thedigitalcatonline.com/blog/2015/04/07/99-scala-problems-07-flatten/#.WBsDFPl97IU 针…

Given a binary tree, flatten it to a linked list in-place. For example,Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 click to show hints. Subscribe to see which companies asked this question 解答 先序遍历同时把节点都堆到左边,…

Given a binary tree, flatten it to a linked list in-place. For example,Given 1 / \ 2 5 / \ \ 3 4 6   The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 Hints: If you notice carefully in the flattened tree, each node's right child points to th…

题目: Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 Hints: If you notice carefully in the flattened tree, each node's right child points to…

根据提示,本题等价于pre order traverse遍历,并且依次把所有的节点都存成right child,并把left child定义成空集.用递归的思想,那么如果分别把左右子树flatten成list,我们有: 1 /    \ 2     5 \       \ 3      6 <- rightTail \ 4  <- leftTail 所以使用递归的解法一: 注意由于右子树最后要接到左子树的后面,所以用temp保存右子树的head. def flatten(self, root)…