题目: Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +, - and *. Example 1: Input: "2-1-1" Output: [0, 2] Explanation: ((2…

给定一个含有数字和运算符的字符串,为表达式添加括号,改变其运算优先级以求出不同的结果.你需要给出所有可能的组合的结果.有效的运算符号包含 +, - 以及 * . 示例 1: 输入: "2-1-1" 输出: [0, 2] 解释: ((2-1)-1) = 0 (2-(1-1)) = 2 示例 2: 输入: "2*3-4*5" 输出: [-34, -14, -10, -10, 10] 解释: (2*(3-(4*5))) = -34 ((2*3)-(4*5)) = -14…

lc 241 Different Ways to Add Parentheses 241 Different Ways to Add Parentheses Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are…

Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +, - and *. Example 1: Input: "2-1-1" Output: [0, 2] Explanation: ((2-1)-…

Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are+, - and *. Example 1 Input: "2-1-1". ((2-1)-1) = 0 (2-(1-1)) = 2 Output: …

https://leetcode.com/problems/different-ways-to-add-parentheses/ Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +, - and *. E…

Problem: Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +, - and *. Example 1 Input: "2-1-1". ((2-1)-1) = 0 (2-(1-1)) =…

96. Unique Binary Search Trees https://www.cnblogs.com/grandyang/p/4299608.html 3由dp[1]*dp[1].dp[0]*dp[2].dp[2]*dp[0]相加而成 从2开始 class Solution { public: int numTrees(int n) { vector<); dp[] = ; dp[] = ; ;i <= n;i++){ ;j < i;j++){ dp[i] += dp[j] *…

241. Different Ways to Add Parentheses https://leetcode.com/problems/different-ways-to-add-parentheses/ 思路就是:首先找到以运算符为根节点,分别计算左子串和右子串的所有结果的集合,然后依次进行组合计算.参考博客http://www.cnblogs.com/ganganloveu/p/4681439.html. 自己的思路错了,直接用两边只用了一个整数去接收左右子串的计算值!! #include…

241. 为运算表达式设计优先级 给定一个含有数字和运算符的字符串,为表达式添加括号,改变其运算优先级以求出不同的结果.你需要给出所有可能的组合的结果.有效的运算符号包含 +, - 以及 * . 示例 1: 输入: "2-1-1" 输出: [0, 2] 解释: ((2-1)-1) = 0 (2-(1-1)) = 2 示例 2: 输入: "23-45" 输出: [-34, -14, -10, -10, 10] 解释: (2*(3-(4*5))) = -34 ((2*3…