Find the total area covered by two rectilinear rectangles in a2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Assume that the total area is never beyond the maximum possible value of int. Cre…

Rectangle Area Find the total area covered by two rectilinear rectangles in a 2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Assume that the total area is never beyond the maximum possible v…

Description:https://leetcode.com/problems/rectangle-area/ public class Solution { public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) { int area = (C-A)*(D-B) + (G-E)*(H-F); if (A >= G || B >= H || C <= E || D <= F)…

题意: 分别给出两个矩形的左下点的坐标和右上点的坐标,求他们覆盖的矩形面积? 思路: 不需要模拟,直接求重叠的部分的长宽就行了.问题是如果无重叠部分,注意将长/宽给置为0. class Solution { public: int getArea(int A,int B,int C,int D){return (C-A)*(D-B);} int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) { ; ; re…

We are given a list of (axis-aligned) rectangles.  Each rectangle[i] = [x1, y1, x2, y2] , where (x1, y1) are the coordinates of the bottom-left corner, and (x2, y2) are the coordinates of the top-right corner of the ith rectangle. Find the total area…

Find the total area covered by two rectilinearrectangles in a 2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Example: Input: A = -3, B = 0, C = 3, D = 4, E = 0, F = -1, G = 9, H = 2 Output:…

223. 矩形面积 223. Rectangle Area 题目描述 在二维平面上计算出两个由直线构成的矩形重叠后形成的总面积. 每个矩形由其左下顶点和右上顶点坐标表示,如图所示. LeetCode223. Rectangle Area中等 示例: 输入: -3, 0, 3, 4, 0, -1, 9, 2 输出: 45 说明: 假设矩形面积不会超出 int 的范围. Java 实现 class Solution { public int computeArea(int A, int B, int…

Contains Duplicate Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. 思路:简单题用set bool cont…

Rectangle Area Find the total area covered by two rectilinear rectangles in a 2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Example: Input: A = -3, B = 0, C = 3, D = 4, E = 0, F = -1, G = 9…

A rectangle is represented as a list [x1, y1, x2, y2], where (x1, y1) are the coordinates of its bottom-left corner, and (x2, y2) are the coordinates of its top-right corner. Two rectangles overlap if the area of their intersection is positive.  To b…

Find the total area covered by two rectilinear rectangles in a 2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Assume that the total area is never beyond the maximum possible value of int. 这道…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Find the total area covered by two rectilinear rectangles in a 2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址: https://leetcode.com/problems/rectangle-area/description/ 题目描述: Find the total area covered by two rectilinear rectangles in a 2D plane. Each rectangle is defined by its bottom left corner…

Find the total area covered by two rectilinear rectangles in a 2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Assume that the total area is never beyond the maximum possible value of int. Cr…

Find the total area covered by two rectilinear rectangles in a 2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Assume that the total area is never beyond the maximum possible value of int. 解法…

Find the total area covered by two rectilinear rectangles in a 2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Assume that the total area is never beyond the maximum possible value of int. 本题…

Find the total area covered by two rectilinear rectangles in a 2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Assume that the total area is never beyond the maximum possible value of int. So…

题目描述: Find the total area covered by two rectilinear rectangles in a 2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Assume that the total area is never beyond the maximum possible value of i…

Find the total area covered by two rectilinear rectangles in a 2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Assume that the total area is never beyond the maximum possible value of int. 题目…

Find the total area covered by two rectilinear rectangles in a 2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Assume that the total area is never beyond the maximum possible value of int. 对于…

题目链接 题目要求: Find the total area covered by two rectilinear rectangles in a 2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Assume that the total area is never beyond the maximum possible value…

题目: Find the total area covered by two rectilinear rectangles in a 2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Assume that the total area is never beyond the maximum possible value of int…

Given a set of points in the xy-plane, determine the minimum area of a rectangle formed from these points, with sides parallel to the x and y axes. If there isn't any rectangle, return 0. Example 1: Input: [[1,1],[1,3],[3,1],[3,3],[2,2]] Output: 4 Ex…

给定一些矩形2 求覆盖面积 矩形不超过200个 1 算法1 朴素思想 虽然朴素但是代码却有意思 利用容斥原理 复杂度高达 N*2^N class Solution: def intersect(rec1,rec2): return [max(rec1[1],rec2[1]), max(rec1[2],rec2[2]), min(rec1[3],rec2[3]), min(rec1[4],rec2[4] ] #这里是两个矩形的两点式求 矩形的相交子矩形 *非常值得思考 def area(rec):…

aaarticlea/png;base64,iVBORw0KGgoAAAANSUhEUgAABRQAAAQ0CAYAAAAPPZBqAAAMFGlDQ1BJQ0MgUHJvZmlsZQAASImVlw…

把交叉点的坐标求出来即可. #define max(a,b) ( (a)>(b)?(a):(b) ) #define min(a,b) ( (a)<(b)?(a):(b) ) int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) { int downx,downy,upx,upy; int crossArea; int all; downx=max(A,E); downy=max(B,F); upx =m…

#-*- coding: UTF-8 -*-#先判断是否有重叠class Solution(object):    def computeArea(self, A, B, C, D, E, F, G, H):        """        :type A: int        :type B: int        :type C: int        :type D: int        :type E: int        :type F: int     …

翻译 找到在二维平面中两个相交矩形的总面积. 每一个矩形都定义了其左下角和右上角的坐标. (矩形例如以下图) 如果,总占地面积永远不会超过int的最大值. 原文 分析 这题前天试过,写了一堆推断.终究还是无果-- 贴几个别人的解决方式-- int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) { int64_t xmin1 = min( A, C ); int64_t xmax1 = max( A, C )…

/* 像是一道数据分析题 思路就是两个矩形面积之和减去叠加面积之和 */ public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) { //求两个面积 int a1 = (C-A)*(D-B); int a2 = (G-E)*(H-F); //求叠加面积,(低上限-高下限)*(左右线-右左线) int h1 = Math.min(D,H); int h2 = Math.max(B,F); int…

题目: Find the total area covered by two rectilinear rectangles in a 2D plane. Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Assume that the total area is never beyond the maximum possible value of int…