org.hibernate.hql.internal.ast.QuerySyntaxExceptionunexpected token: on near line 1

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org.hibernate.hql.internal.ast.QuerySyntaxExceptionunexpected token: on near line 1

select d.content,count(s.status) from MesmachineStatus s , Mesmachinestatusdetail d where s.status=d.status group by s.status 正确地 SELECT d.content,count(s.status)from Mes_machinestatus s left JOIN mes_machinestatusdetail d on s.status=d.status GROUP…

ERROR org.hibernate.hql.internal.ast.ErrorCounter unexpected token: form 异常解决

ERROR org.hibernate.hql.internal.ast.ErrorCounter unexpected token: form 异常解决根据异常提示:我找了我的MySQL语句:果然找到了将FORM修改为FROM后运行就对了这些都是粗心导致,希望我能记住这个错误. 我百度了一下,发现还有许多类似的错误总结: ERROR org.hibernate.hql.internal.ast.ErrorCounter :unexpected token: xxxx 解决办法: 1.首…

SSH整合报错：org.hibernate.hql.internal.ast.QuerySyntaxException: User is not mapped[......]

非常诡异的报错,信息如下:org.hibernate.hql.internal.ast.QuerySyntaxException: User is not mapped [select count(*) from User u where u.userName=? and u.userPassword=? ]Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: User is not mapped类似的报错信息的解决方法,…

WebLogic使用SSH架构部署遇到org.hibernate.hql.internal.ast.HqlTok

其实这个问题在以前就遇到过,当时解决了,但今天在部署一个测试轻应用的时候一直没有想起来,特此记录一下. 这个问题出现在使用WebLogic(我使用的是10.3.5版本)发布SSH架构的应用.在操作数据库的时候使用Hibernate配合JPA实现.发布之后无法从数据库获取数据,从日志看到故障提示org.hibernate.QueryException: ClassNotFoundException: org.hibernate.hql.internal.ast.HqlTok 这个错误的根本原因是w…

org.hibernate.hql.internal.ast.QuerySyntaxException: XXX is not mapped

异常情况: 最近在把一个项目拆分多个 module 的时候数据库查询遇到这个异常:org.hibernate.hql.internal.ast.QuerySyntaxException: Identification is not mapped JPA 查询方法如下: public Identification findIdentificationByWxId(String wxId) { JPAQueryBase query = new JPAQuery(entityManager).from…

继承映射中的java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: person is not mapped [FROM person]

继承映射中查询对象的过程中报错: java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: person is not mapped [FROM person] HQL查询的是持久化类名而不是表名, List<Person> persons=session.createQuery("FROM person").list(); 所以应该改为from Per…