zhx's submissions Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 540    Accepted Submission(s): 146 Problem Description As one of the most powerful brushes, zhx submits a lot of code on many o…

Problem Description As one of the most powerful brushes, zhx submits a lot of code on many oj and most of them got AC. One day, zhx wants to count how many submissions he made on n ojs. He knows that on the ith oj, he made ai submissions. And what yo…

http://acm.hdu.edu.cn/showproblem.php?pid=5186 题意是分别对每一位做b进制加法,但是不要进位 模拟,注意:1 去掉前置0 2 当结果为0时输出0,而不是全部去掉 #include <cstdio> #include <cstring> #include <algorithm> using namespace std; const int maxn=101; const int maxm=201; int n,b; char…

zhx's contest Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 448    Accepted Submission(s): 147 Problem Description As one of the most powerful brushes, zhx is required to give his juniors n p…

Problem Description As one of the most powerful brushes, zhx is required to give his juniors n problems. zhx thinks the ith problem's difficulty is i. He wants to arrange these problems in a beautiful way. zhx defines a sequence {ai} beautiful if the…

zhx's submissions Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2293    Accepted Submission(s): 641 Problem Description As one of the most powerful brushes, zhx submits a lot of code on many o…

传送门 zhx and contest Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 145    Accepted Submission(s): 49 Problem Description As one of the most powerful brushes in the world, zhx usually takes part…

传送门 zhx's contest Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 575    Accepted Submission(s): 181 Problem Description As one of the most powerful brushes, zhx is required to give his juniors…

pid=3966" target="_blank" style="">题目链接:hdu 3966 Aragorn's Story 题目大意:给定一个棵树,然后三种操作 Q x:查询节点x的值 I x y w:节点x到y这条路径上全部节点的值添加w D x y w:节点x到y这条路径上全部节点的值降低w 解题思路:树链剖分,用树状数组维护每一个节点的值. #pragma comment(linker, "/STACK:1024000000,1…

HDU Aragorn's Story 题目链接 树抛入门裸题,这题是区间改动单点查询,于是套树状数组就OK了 代码: #include <cstdio> #include <cstring> #include <vector> #include <algorithm> using namespace std; const int N = 50005; inline int lowbit(int x) {return x&(-x);} int dep…