Number Sequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 86102 Accepted Submission(s): 20423 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n…
A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n). InputThe input consists of multiple test cases. Each test case contains 3 integers A,…
传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1005 Number Sequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 198316 Accepted Submission(s): 49744 Problem Description A number sequence…
Number Sequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 176080 Accepted Submission(s): 43527 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (…
f(n-1)和f(n-2)所有组合都49种子,这期可达49,但f(n-1)=f(n-2)=0如果是,列的总数目0.话题条件f(1)=f(2)=1.因此排除这样的情况.的最长期限48. #include<math.h> #include<stdio.h> #include<stdlib.h> #include<string.h> int main(void) { int a,b,n; int f[99]; while(scanf("%d%d%d&qu…
Number Sequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 154923 Accepted Submission(s): 37854 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A…
找规律,先找属于第几个循环,再找属于第几个数的第几位...... Number Sequence Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 31552 Accepted: 8963 Description A single positive integer i is given. Write a program to find the digit located in the position i in the sequ…
Number Sequence Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 8600 Accepted Submission(s): 3953 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[…
Number Sequence A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n). Input The input consists of multiple test cases. Each test case co…