YTU 2732:3798-Abs Problem】的更多相关文章

Abs Problem Time Limit: 2 Seconds      Memory Limit: 65536 KB      Special Judge Alice and Bob is playing a game, and this time the game is all about the absolute value! Alice has N different positive integers, and each number is not greater than N.…
2732: 3798-Abs Problem 时间限制: 1 Sec  内存限制: 128 MB  Special Judge 提交: 167  解决: 60 题目描述 Alice and Bob is playing a game, and this time the game is all about the absolute value! Alice has N different positive integers, and each number is not greater than…
Problem A: WERTYU Description A common typing error is to place yourhands on the keyboard one row to the right of the correct position. Then ``Q'' is typed as ``W'' and ``J'' is typed as ``K'' and so on. Your task is to decode a message typed inthis…
1001: A+B Problem 时间限制: 1 Sec  内存限制: 10 MB 提交: 4864  解决: 3132 [提交][状态][讨论版] 题目描述 Calculate a+b 输入 Two integer a,b (0<=a,b<=10) 输出 Output a+b 样例输入 1 2 样例输出 3 迷失在幽谷中的鸟儿,独自飞翔在这偌大的天地间,却不知自己该飞往何方-- #include <iostream> using namespace std; int main(…
1012: A MST Problem 时间限制: 1 Sec  内存限制: 32 MB 提交: 7  解决: 4 题目描述 It is just a mining spanning tree ( 最小生成树 ) problem, what makes you a little difficult is that you are in a 3D space. 输入 The first line of the input contains the number of test cases in t…
A Abs Problem http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=5330 找规律题,构造出解.copyright@ts #include<cstdio> int main() { int n,big,sma,id; while(~scanf("%d",&n)) { ) { puts("1 1"); puts("); puts("); contin…
Abs Problem Time Limit: 2 Seconds Memory Limit: 65536 KB Special Judge Alice and Bob is playing a game, and this time the game is all about the absolute value! Alice has N different positive integers, and each number is not greater than N. Bob has a…
Contest Link Official Editorial 比赛体验良好,网站全程没有挂.题面简洁好评,题目质量好评.对于我这个蒟蒻来说非常合适的一套题目. A. Simple Math Problem Link Description Given are three positive integers \(A,B,\) and \(C\) . Compute the following value modulo \(998244353:\sum_{a=1}^A\sum_{b=1}^B\su…
1098: The 3n + 1 problem 时间限制: 1 Sec  内存限制: 64 MB 提交: 368  解决: 148 题目描述 Consider the following algorithm to generate a sequence of numbers. Start with an integer n. If n is even, divide by 2. If n is odd, multiply by 3 and add 1. Repeat this process…
Description Graphical editors such as Photoshop allow us to alter bit-mapped images in the same way that text editors allow us to modify documents. Images are represented as an M x N array of pixels, where each pixel has a given color. Your task is t…
POJ 2711 Leapin' Lizards / HDU 2732 Leapin' Lizards / BZOJ 1066 [SCOI2007]蜥蜴(网络流,最大流) Description Your platoon of wandering lizards has entered a strange room in the labyrinth you are exploring. As you are looking around for hidden treasures, one of…
题目 Source http://codeforces.com/problemset/problem/713/C Description Sonya was unable to think of a story for this problem, so here comes the formal description. You are given the array containing n positive integers. At one turn you can pick any ele…
http://acm.hdu.edu.cn/showproblem.php?pid=2732 题意:给出两个地图,蜥蜴从一个柱子跳跃到另外一个地方,那么这个柱子就可能会坍塌,第一个地图是柱子可以容忍跳跃多少次(即从它为起点可以跳跃多少次,然后坍塌),第二个地图是蜥蜴的位置.还有一个跳跃距离d,即蜥蜴可以跳跃不超过d的距离(曼哈顿距离),如果跳到地图外面,即蜥蜴逃跑成功,问最终留下的蜥蜴数最少是多少. 思路:我觉得如果不是在做网络流套题应该想不到这是网络流.其实挺简单的建图.首先考虑蜥蜴的位置,和…
题意:建一个家庭树,找出有第d代子孙的名字,按照要求的第d代子孙的数从大到小输出三个人名,如果有一样大小子孙数的,就按字母序从小到大将同等大小的都输出,如果小于三个人的就全输出. 题目链接:http://poj.org/problem?id=2732 分析:数据量很小,直接建树,枚举暴力输出.我直接套模板用map建树的. 注意:1.每次测试数据时要清空map和vector!!! 2.注意输出要从大到小输出答案,如果答案有一样的按名字的字母序从小到大输出.答案用vector保存,vector排序:…
E. Sonya and Problem Wihtout a Legend time limit per test 5 seconds memory limit per test 256 megabytes input standard input output standard output Sonya was unable to think of a story for this problem, so here comes the formal description. You are g…
http://codeforces.com/contest/472/problem/D D. Design Tutorial: Inverse the Problem time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output There is an easy way to obtain a new task from an old on…
题目链接: C. Sonya and Problem Wihtout a Legend time limit per test 5 seconds memory limit per test 256 megabytes input standard input output standard output Sonya was unable to think of a story for this problem, so here comes the formal description. You…
Problem A: Jolly Jumpers Time Limit: 1 Sec  Memory Limit: 64 MBSubmit: 10  Solved: 4[Submit][Status][Web Board] Description A sequence of n > 0 integers is called a jolly jumper if the absolute values of the differences between successive elements ta…
Fast Food Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit Status Practice UVA 662 Appoint description:  System Crawler  (2015-08-27) Description   The fastfood chain McBurger owns several restaurants along a highway. Rec…
题目链接:http://poj.org/problem?id=1681 题意:还是翻格子的题,但是这里有可能出现自由变元,这时候枚举一下就行..(其实这题直接状压枚举就行) /* ━━━━━┒ギリギリ♂ eye! ┓┏┓┏┓┃キリキリ♂ mind! ┛┗┛┗┛┃\○/ ┓┏┓┏┓┃ / ┛┗┛┗┛┃ノ) ┓┏┓┏┓┃ ┛┗┛┗┛┃ ┓┏┓┏┓┃ ┛┗┛┗┛┃ ┓┏┓┏┓┃ ┛┗┛┗┛┃ ┓┏┓┏┓┃ ┃┃┃┃┃┃ ┻┻┻┻┻┻ */ #include <algorithm> #include…
原题链接:http://poj.org/problem?id=2826 一题很蛋疼的一题.目前为止还有一个问题我没搞清楚,问题注在代码中. 题目大意: 外面下雨了,农民Johnoson的bull(??是什么)Ben要接点雨水去浇花.Ben拿两个木板在墙上,如图所示,墙上的两块木板可以看作是空中的两条线段,它们有一定的宽度. 你的任务是计算两块木板能接多少水. 最后要计算两块木板能装水的部分的面积.但是要注意一种情况,雨是垂直往下滴的,如果装水的部分没有雨能够进去的话,也是接不到水的.如图: 这种…
//把一个序列转换成严格递增序列的最小花费 CF E - Sonya and Problem Wihtout a Legend //dp[i][j]:把第i个数转成第j小的数,最小花费 //此题与poj 3666相似 a[i]转换成a[i]-i #include <iostream> #include <cstdio> #include <cstdlib> #include <algorithm> #include <vector> #inclu…
Painter's Problem 题意:给一个n*n(1 <= n <= 15)具有初始颜色(颜色只有yellow&white两种,即01矩阵)的square染色,每次对一个方格染成黄色时,同时会把周围的方格也染成黄色.(这和1222的开关一样的关联关系)问最后可以将square全部染成黄色的最小染色方格数? 思路: 1.直接预处理出增广矩阵,和1222不同的是里面有最优解的条件,贪心的思想是把自由变元看成是没染色的,但是其他非自由变元(除去自由维度之外的变量)是可以通过自由变元的取…
贪心+网络流.对于每个结点,构建入点和出点.对于每一个lizard>0,构建边s->in position of lizard, 容量为1.对于pillar>0, 构建边in position of pillar -> out position of pillar, 容量为number of pillar.若沿四个方向移动距离d可以超过边界,则构建边out position of pillar -> t, 容量为INF:否则, 对于曼哈顿距离l(l>0 and l<…
Description Sonya was unable to think of a story for this problem, so here comes the formal description. You are given the array containing \(n\) positive integers. At one turn you can pick any element and increase or decrease it by \(1\). The goal i…
Mr. Frog's Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 312    Accepted Submission(s): 219 Problem Description One day, you, a clever boy, feel bored in your math class, and then fall…
Ugly Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 0    Accepted Submission(s): 0Special Judge Problem Description Everyone hates ugly problems.You are given a positive integer. You mu…
http://acm.hdu.edu.cn/showproblem.php?pid=4972 ++和+1还是有区别的,不可大意. A simple dynamic programming problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 307    Accepted Submission(s): 117 Problem D…
题目链接: http://acm.fzu.edu.cn/problem.php?pid=2238 题目大意: 已知等差数列A(0)的首项a和公差d,求出数列A(0)前n项和,得到新数列A(1);以此类推,最终求A(m)的第i项mod1000000007 题目思路: [动态规划] 不难推出c[i][j]=c[i-1][j]+c[i][j-1] 但是i太大不能直接递推,m<=1000不能矩阵快速幂. 通过推导可以求出c[i][j]=a*C(n+m-1,n-1)+d*C(n+m-1,n-2) 求模时除…
题目链接: http://codeforces.com/contest/706/problem/C 题目大意: n(2 ≤ n ≤ 100 000)个字符串(长度不超过100000),翻转费用为Ci(<=109),求所有字符串从上到下符合字典序从小到大的最小费用.无解输出-1. 题目思路: [动态规划] 每个字符串有2种状态,翻转或者不翻转,每次只与上一个字符串是否翻转有关,可以用DP. 费用很大,要用long long. 无解的时候我直接break了WA了好久. // //by coolxxx…