[ 声明:版权全部,转载请标明出处,请勿用于商业用途.  联系信箱:libin493073668@sina.com] 题目链接:https://leetcode.com/problems/implement-strstr/ 题意: 给定两个串,判定needle串是否haystack串的子串,假设是,返回匹配的起始位置.假设不是,则返回-1 思路: 直接两个循环暴力解决 class Solution { public: int strStr(string haystack, string need…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 28: Implement strStr()https://oj.leetcode.com/problems/implement-strstr/ Implement strStr().Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of h…

28. Implement strStr() Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. 思路:子串匹配,朴素匹配.…

28. Implement strStr()[easy] Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. 解法一: class Solution { public: int strStr(string haystack, string needle) { if (haystack.empty()…

1.题目 28. Implement strStr()——Easy Implement strStr(). Return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. Example 1: Input: haystack = "hello", needle = "ll" Output: 2 Example 2: Inp…

28.Implement strStr() Implement strStr(). Return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. Example 1: Input: haystack = "hello", needle = "ll" Output: 2 Example 2: Input: haystack…

Implement strStr(). Return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. Example 1: Input: haystack = "hello", needle = "ll" Output: 2 Example 2: Input: haystack = "aaaaa",…

Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. 1 class Solution(object): def strStr(self, haystack, needle): """ :type haystack: str :type needle: str :rtype: in…

Brute Force算法,时间复杂度 O(mn) def strStr(haystack, needle): m = len(haystack) n = len(needle) if n == 0: return 0 if m < n: return -1 for i in range(m - n - 1): for j in range(n): if haystack[i + j] != needle[j]: break elif j == n - 1: return i return -1…

Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. Solution:  class Solution { public: int strStr(string haystack, string needle) { //runtime:4ms int len1=haystack.size(), len…