传送门 分析 我们先考虑暴力如何计算 对于S的子串SS,如果它有位置i使得SS[i] != T[i]那么我们就将两个字符之间用并查集连边 最后答案很明显就是并查集中所有边的个数 于是我们可以发现对于S[i] != T[j]衣服那个会在S的第i-j个子串连边 我们通过观察可以发现i - j = i - (m - j) +m 这是一个卷积的形式 于是我们枚举S和T中考虑的是那种字符然后卷积判断连边关系 最后进行之前说的并查集即可 代码 #include<iostream> #include<…

题目链接  Educational Codeforces Round 40  Problem I 题意  定义两个长度相等的字符串之间的距离为:   把两个字符串中所有同一种字符变成另外一种,使得两个字符串相等所需要操作的次数的最小值.   求$s$中每一个长度为$t$的长度的连续子串与$t$的距离.字符集为小写字母$a$到$f$ 首先解决求两个长度相等的字符串之间的距离这个问题. $s$和$t$相同位上的字母连一条无向边,最后的答案是$s$和$t$中所有出现过的字符的个数减去这个无向图的连通块…

题目链接 \(Description\) 对于两个串\(a,b\),每次你可以选择一种字符,将它在两个串中全部变为另一种字符. 定义\(dis(a,b)\)为使得\(a,b\)相等所需的最小修改次数. 给定两个串\(S,T\),对于\(S\)中所有长为\(|T|\)的子串\(S'\),输出\(dis(S',T)\). \(1\leq|T|\leq|S|\leq125000\),字符集为\(a\sim f\). \(Solution\) 考虑\(dis(a,b)\)怎么求.用一个并查集,依次枚举\…

[CF954I]Yet Another String Matching Problem(FFT) 题面 给定两个字符串\(S,T\) 求\(S\)所有长度为\(|T|\)的子串与\(T\)的距离 两个等长的串的距离定义为最少的,将某一个字符全部视作另外一个字符的次数. \(|T|<=|S|<=10^6\),字符集大小为\(6\) 题解 考虑如何快速计算两个串的答案,从左向右扫一遍,如果对应位置上有两个字符不同,检查在并查集中是否属于同一个集合,如果不属于则答案加一,同时合并两个集合.(这个就是…

传送门 题意:给出两个由小写$a$到$f$组成的字符串$S$和$T$($|S| \geq |T|$),给出变换$c1\,c2$表示将两个字符串中所有$c1$字符变为$c2$,求$S$的每一个长度为$T$的子串与$T$做变换使得两个字符串相等的最小变换次数.$1 \leq |T| \leq |S| \leq 1.25 \times 10^5$ 弱化版:CF939D PS:默认字符串开头是第$0$位 我们同样考虑通过CF939D的那种方法解决这个问题.考虑到这道题的字符集大小只有$6$,也就是说本质…

http://codeforces.com/contest/954/problem/I 给你两个串s,p,求上一个串的长度为|p|的所有子串和p的差距是多少,两个串的差距就是每次把一个字符变成另一个字符的最小次数,字符最大到f 很明显,如果知道每两个串对应地方不相同的字符就能通过dfs/dsu解出来,那么如何快速的找到所有对应的不匹配的地方呢, 我们先单独考虑两个不同的字符,比如abada中取a,cba中取c,用二进制1代表选取的字符表示就是10101,100,我们用fft来加速这一过程 1 2…

传送门 每次操作可以把两个字符串中所有同一种字符变成另外一种 定义两个长度相等的字符串之间的距离为:使两个字符串相等所需要操作的次数的最小值 求 \(s\) 中每一个长度为 \(|t|\) 的连续子串与 \(t\) 的距离 字符集为小写字母 \('a'\) 到 \('f'\) Sol 考虑如何计算两个等长串的距离 相当于两个匹配的字符之间连边,同一个连通块内可以互相转化,答案就是并查集合并的次数 本题的字符集大小只有 \(6\),那么考虑枚举两种字符匹配连边 匹配就是一个非常套路的反转 \(+\…

给定两个字符串\(S,T\) 求\(S\)所有长度为\(|T|\)子串与\(T\)的距离 两个等长的串的距离定义为最少的,将某一个字符全部视作另外一个字符的次数. \(|T|<=|S|<=10^6\),字符集大小为\(6\) 题解 首先考虑对于两个长度相等的子串怎么比较他们的距离,那么就是一个CF939D Love Rescue,一遍扫过去,如果对应位置的字符不相等且不在同一个并查集内那么连边并\(++ans\) 因为字符集大小只有\(6\),边的种类只有\(30\)种,所以我们可以考虑对于每…

Problem Description String matching is a common type of problem in computer science. One string matching problem is as following: Given a string s[0…len−1], please calculate the length of the longest common prefix of s[i…len−1] and s[0…len−1] for eac…

Binary String Matching 时间限制:3000 ms  |  内存限制:65535 KB 难度:3 描述     Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘10011…

String Matching Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 847    Accepted Submission(s): 434 Problem Description It's easy to tell if two words are identical - just check the letters. But…

问题 B: Binary String Matching 时间限制: 3 Sec  内存限制: 128 MB提交: 4  解决: 2[提交][状态][讨论版] 题目描述 Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text…

Binary String Matching 时间限制:3000 ms  |  内存限制:65535 KB 难度:3   描述 Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110…

Binary String Matching 时间限制:3000 ms  |  内存限制:65535 KB 难度:3   描述 Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110…

Binary String Matching 时间限制:3000 ms  |  内存限制:65535 KB 难度:3   描述 Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110…

Aho - Corasick string matching algorithm 俗称:多模式匹配算法,它是对 Knuth - Morris - pratt algorithm (单模式匹配算法) 形成多模式匹配算法的一种改进,如果我们用单模式匹配算法实现多模式匹配算法,假如模式串有 M 个 , 则需要重复调用 M 次单模式匹配算法 : 举个很简单的例子,假如我现在有一本特殊的字典,字典中的词汇就是所有的模式串,然后给你一篇文章(全英文),让你查一下这篇文章中有多少个词汇在字典中可以查得到:(为…

String Matching Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 4074   Accepted: 2077 Description It's easy to tell if two words are identical - just check the letters. But how do you tell if two words are almost identical? And how close…

hihocoder #1059 :String Matching Content Length 时间限制:10000ms 单点时限:1000ms 内存限制:256MB 描述 We define the matching contents in the strings of strA and strB as common substrings of the two strings. There are two additional restrictions on the common substr…

Binary String Matching 时间限制:3000 ms  |  内存限制:65535 KB 难度:3   描述 Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110…

5-Binary String Matching 内存限制:64MB 时间限制:3000ms 特判: No通过数:232 提交数:458 难度:3 题目描述: Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text stri…

/*String Matching Description It's easy to tell if two words are identical - just check the letters. But how do you tell if two words are almost identical? And how close is "almost"?  There are lots of techniques for approximate word matching. O…

Binary String Matching 时间限制:3000 ms  |  内存限制:65535 KB 难度:3   描述 Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110…

Binary String Matching 时间限制:3000 ms  |  内存限制:65535 KB 难度:3   描述 Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110…

Binary String Matching 时间限制:3000 ms  |  内存限制:65535 KB 难度:3  描述:Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For             example, the text string B…

Binary String Matching 时间限制:3000 ms  |  内存限制:65535 KB 难度:3   描述 Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110…

Binary String Matching 时间限制:3000 ms  |  内存限制:65535 KB 难度:3   描述 Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110…

String Matching Input The input consists of several test cases. Each test case consists of two lines, first a non-empty pattern, then a non-empty text. Input is terminated by end-of-file. The input file will not be larger than 5 Mb. Output For each t…

string matching exkmp #include<bits/stdc++.h> using namespace std; ; int Nex[maxn],extend[maxn]; void getNex(char str[]) { ,j,po,len=strlen(str); Nex[]=len; ]&&i+<len) { i++; } Nex[]=i; po=; ; i<len; i++) { if(Nex[i-po]+i<Nex[po]+po…

时间限制:1 秒 内存限制:32 兆 特殊判题:否 提交:1259 解决:686 题目描述: Finding all occurrences of a pattern in a text is a problem that arises frequently in text-editing programs.      Typically,the text is a document being edited,and the pattern searched for is a particula…

预处理下连续相等的字符个数其实主要是看是否满3个 后面递推的时候特判下+1上次递推[i-1,j-1]不是来自[i-2,j-1]也不是来自[i-1,j-2]其实就是只来自[i-4,j-4]+3,和[i-2,j-2]+1这样才能保证连续让长度超过3的继续增加1 但是这里不通过直接[i-4,j-4]+3==[i-1,j-1]判断因为不满足3的不算进来,比如[0,0]+3==[3,3]可以但是[1,1]+3!=[4,4]因为[1,1]也是0,就不能推出[5,5]了,当然也可以用[3,3]+1==[4,4…