Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". bool isAllZero(string a) { for (int i = 0; i < a.length(); ++i) { if (a[i] != '0')return false; } return true;…
顺便把之前做过的一个简单难度的题也贴上来吧 67. Add Binary Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 这种问题 其实大多数人都做烂了 但是在实际应用中这个问题应用很广泛 有用二进制数基本就要处理加减乘除 一种最容易理解的方法但是不高效 那就是转为十进制处理后再转…
Given two binary strings, return their sum (also a binary string). Have you met this question in a real interview? Yes Example a = 11 b = 1 Return 100 LeetCode上的原题,请参见我之前的博客Add Binary. class Solution { public: /** * @param a a number * @param b a num…
Add Binary https://leetcode.com/problems/add-binary/ Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 算法 1) 假设aLen表示string a的长度,那么它的第aLen - 1个元素表示的最低位:string b同 2)…
1 题目 Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 接口 String addBinary(String a, String b) 2 思路 处理二进制求和和进位.从低位开始,一直相加并且维护进位.和Add Two Numbers的区别是这个题目低位在后面,所以要从strin…
67. Add Binary Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". public class Solution { public String addBinary(String a, String b) { String res =""; int l1…
Add BinaryGiven two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". SOLUTION: 指针指到两个字符串的末尾,不断往前推进,用carry表示进位.用stringbuilder来记录结果. 使用insert(0, c)函数将加出的结果不断插入到STRINGBUILDER. pub…
一.题目描写叙述 Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 二.解题技巧 这道题考察两个二进制数相加,考虑到输入的是两组string,同一时候注意在运算时从左到右各自是从低位到高位,因此须要考虑对输入进行翻转处理,中间二进制树相加部分没有过多的设计障碍.主要是计算进位:…
Leetcode 67:Add Binary(二进制求和) (python.java) Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. 给定两个二进制字符串,返回他们的和(用二进制表示). 输入为非空字符串且只包含数字 1 和 0. Example 1: Input…
67. Add Binary Easy Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Inp…
1.题目 67. Add Binary——easy Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1"Output: "100"Example 2:…
package addBinary67;/* Given two binary strings, return their sum (also a binary string).For example,a = "11"b = "1"Return "100". */public class Solution { public static String addBinary(String a, String b) { //ensure a.lengt…
Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 详细一位一位地加即可了,考虑进位的问题.还有最后记得把生成的string反过来再返回,由于我们是从最低位開始加的. public class Solution { public String addBinary(String a…
题目: Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 题解: 二进制加法都是从最低位(从右加到左).所以对两个字符串要从最后一位开始加,如果遇见长度不一的情况,就把短的字符串高位补0. 每轮计算要加上进位,最后跳出循环后要坚持进位是否为1,以便更新结果. 代码如下(from…
Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". Hide Tags Math String class Solution { public: string addBinary(string a, string b) { string longer=a.length()>b.l…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 BigInteger类 模拟加法 日期 题目地址:https://leetcode.com/problems/add-binary/description/ 题目描述 Given two binary strings, return their sum (also a binary string). The input strings are bot…
Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 二进制数想加,并且保存在string中,要注意的是如何将string和int之间互相转换,并且每位相加时,会有进位的可能,会影响之后相加的结果.而且两个输入string的长度也可能会不同.这时我们需要新建一个string,它的长度是两…
题目简述: Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 解题思路: class Solution: # @param a, a string # @param b, a string # @return a string def addBinary(self, a, b)…
Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". class Solution { public: string addBinary(string a, string b) { , alen = a.length(),blen = b.length(); string res=&qu…
Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 算法:模拟加法过程 class Solution { public: string addBinary(string a, string b) { int len1=a.size(); int len2=b.size(); ; rev…
Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 解题思路: JAVA实现如下: static public String addBinary(String a, String b) { if (a.length() < b.length()) { String temp…
Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 这个题目只要注意各种情况你就成功了一大半,特别要注意的是对进位赋值后可能产生的变化,以及最后一位进位为1时, 我们要把这个1插进来.同时注意字符串的低位是我们数值的高位 class Solution { public: string…
题目: Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 代码: class Solution { public: string addBinary(string a, string b) { std::string result; std::string::reverse_iter…
66 - Plus One Given a non-negative number represented as an array of digits, plus one to the number. The digits are stored such that the most significant digit is at the head of the list. Solution 1 : 十进制加法 class Solution { public: vector<int> plusO…
题目描述: Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 解题思路: 使用StringBuilder,且使用进位. 代码如下: public class Solution { public String addBinary(String a, String b) { String…
Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 求数字字符串的二进制和. 同之前的数组代表数字,两个数组相加一样.仅仅只是进位变成了2.可能两个串的长度不一样,故逆转.从左到右加下去.最后再逆转. public static String addBinary(String a…
题目: Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 提示: 此题我的第一反应是把输入的两个字符串转化为数字,相加以后再把结果转化为二进制输出,但是测试用例中会有很大的输入,此时即使是long long型也会造成溢出,所以只能用最传统的由低位到高位逐位相加的方法去做. 代码: c…