题目传送门  Prime Path The ministers of the cabinet were quite upset by the message from the Chief of Security stating that they would all have to change the four-digit room numbers on their offices. — It is a matter of security to change such things ever…

Prime Path Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 987    Accepted Submission(s): 635 Problem Description The ministers of the cabinet were quite upset by the message from the Chief of S…

Prime Path Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 21   Accepted Submission(s) : 18 Problem Description The ministers of the cabinet were quite upset by the message from the Chief of Sec…

Prime Path 原文是English 这里直接上中文了 Descriptions: 给你两个四位的素数a,b.a可以改变某一位上的数字变成c,但只有当c也是四位的素数时才能进行这种改变.请你计算a最少经过多少次上述变换才能变成b.例如:1033 -> 8179 1033 1733 3733 3739 3779 8779 8179最少变换了6次.Input 第一行输入整数T,表示样例数. (T <= 100) 每个样例输入两个四位的素数a,b.(没有前导零) Output 对于每个样例,输…

题意为给出两个四位素数A.B,每次只能对A的某一位数字进行修改,使它成为另一个四位的素数,问最少经过多少操作,能使A变到B.可以直接进行BFS搜索 #include<bits/stdc++.h> using namespace std; bool isPrime(int n){//素数判断 || n == ) return true; else{ ; ; i < k; i++){ ) return false; } return true; } } ]; ]; void getPrime…

[题目链接]click here~~ [题目大意]给你n,m各自是素数,求由n到m变化的步骤数,规定每一步仅仅能改变个十百千一位的数,且变化得到的每个数也为素数 [解题思路]和poj 3278类似.bfs+queue,分别枚举个十百千的每一位就能够了,只是注意个位仅仅能为奇数,且千位从1開始 代码: #ifndef _GLIBCXX_NO_ASSERT #include <cassert> #endif #include <cctype> #include <cerrno&g…

思路:宽度优先搜索(BFS算法) #include<iostream> #include<stdio.h> #include<cmath> #include<cstring> using namespace std; int a,b; struct node{ int num; int step; }; node que[10000];//默认初始化为0 int visit[10000];//默认初始化为0 int prime(int d){ if(d<…

Description The ministers of the cabinet were quite upset by the message from the Chief of Security stating that they would all have to change the four-digit room numbers on their offices. — It is a matter of security to change such things every now…

Prime Path POJ - 3126 题意: 给出两个四位素数 a , b.然后从a开始,每次可以改变四位中的一位数字,变成 c,c 可以接着变,直到变成b为止.要求 c 必须是素数.求变换次数的最小值.(a,b,c都是四位数字,输入时没有前导零) 分析: 每次改变可以获得一个四位数c,然后如果c是素数并且之前没有出现过,那么我们把它放入队列即可. int f[10001]; int v[10001]; void init()//素数筛 { memset(f,0,sizeof f); fo…

Prime Path Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 27852   Accepted: 15204 Description The ministers of the cabinet were quite upset by the message from the Chief of Security stating that they would all have to change the four-di…