leetcode-158周赛-5223-可以攻击国王的皇后

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leetcode-158周赛-5223-可以攻击国王的皇后

题目描述: 自己的提交: class Solution: def queensAttacktheKing(self, queens: List[List[int]], king: List[int]) -> List[List[int]]: if not queens:return [] res = [] row,col = 8,8 opt = [[0,1],[1,0],[-1,0],[0,-1],[1,1],[1,-1],[-1,1],[-1,-1]] for x,y in opt: i =…

[LeetCode] 495. Teemo Attacking 提莫攻击

In LOL world, there is a hero called Teemo and his attacking can make his enemy Ashe be in poisoned condition. Now, given the Teemo's attacking ascending time series towards Ashe and the poisoning time duration per Teemo's attacking, you need to outp…

✡ leetcode 158. Read N Characters Given Read4 II - Call multiple times 对一个文件多次调用read（157题的延伸题） --------- java

The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the function…

leetcode[158] Read N Characters Given Read4 II - Call multiple times

想了好一会才看懂题目意思,应该是: 这里指的可以调用更多次,是指对一个文件多次操作,也就是对于一个case进行多次的readn操作.上一题是只进行一次reandn,所以每次返回的是文件的长度或者是n,并且将相应的字符存在buf里.现在调用多次的话就可能存在以下的例子: 例如文件case是:1,2,3,4,5,6,7 如果要实现read5,先用read4读四个到buf,再用read4读剩下的3个到buf+4之后,但是read5一次最多读5个到buf,所以read4多读的2个就要存起来,防止下次调用…

[leetcode]158. Read N Characters Given Read4 II - Call multiple times 用Read4读取N个字符2 - 调用多次

The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the function…