The Doors Time Limit: 1000 MS Memory Limit: 10000 KB 64-bit integer IO format: %I64d , %I64u   Java class name: Main [Submit] [Status] [Discuss] Description You are to find the length of the shortest path through a chamber containing obstructing wall…

The Doors Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 5210   Accepted: 2124 Description You are to find the length of the shortest path through a chamber containing obstructing walls. The chamber will always have sides at x = 0, x =…

Question There are 100 doors in a row that are all initially closed. You make 100 passes by the doors. The first time through, visit every door and toggle the door (if the door is closed,open it;if it is open,close it). The second time, only visit ev…

  The Doors Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 7430   Accepted: 2915 Description You are to find the length of the shortest path through a chamber containing obstructing walls. The chamber will always have sides at x = 0, x…

The Doors Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 6734   Accepted: 2670 Description You are to find the length of the shortest path through a chamber containing obstructing walls. The chamber will always have sides at x = 0, x =…

POJ 1556 - The Doors题意:    在 10x10 的空间里有很多垂直的墙,不能穿墙,问你从(0,5) 到 (10,5)的最短距离是多少.    分析:        要么直达,要么一定是墙的边缘点之间以及起始点.终点的连线.        所以先枚举墙上每一点到其他点的直线可达距离,就是要判定该线段是否与墙相交(不含端点).        然后最短路. #include <iostream> #include <cstdio> #include <cmat…

POJThe Doors AND NYIST 有趣的问题 题目链接:pid=227" target="_blank">Click Here~ 题目分析: 给你横纵坐标分别表示门所在的位置.叫你求出从起点到终点的最短距离. 算法分析: 该题好像有多种解法,我仅仅说我做的. 我用的是几何+图论. 建模分析: 1.先推断两个点之间能否够连接. 2.推断两个点能否够链接的方法是用是否推断墙与这两点连成的线段是否相交. 3.假设没有相交则直接连接. 4.最后最短路求出结果就好了…

引言 IBM Rational DOORS,简称DOORS,是被业界广泛认可的需求管理工具,在国内外需求管理领域具有较高的市场占有率.需求管理作为传统的工程领域,理论发展相对成熟和健全.随着越来越多的企业开始注重在需求管理工程层面的投入,企业的需求管理成熟度也在逐步提高.在需求管理实施过程中,不可避免的会依托相关的需求管理工具支撑.而实施过程中所存在的关键困难之一就是:工具与业务如何紧密结合.很多企业虽然购买了相应的产品,但是工具层面的操作培训不足以使得企业的项目在需求管理工具中落地.鉴于此种情…

The Doors Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 8334   Accepted: 3218 Description You are to find the length of the shortest path through a chamber containing obstructing walls. The chamber will always have sides at x = 0, x =…

The Doors 签到题 #include <iostream> using namespace std; int a[200005]; int main() { int n; scanf("%d",&n); for(int i=0;i<n;i++) { scanf("%d",&a[i]); } int x=a[n-1]; int pos=n-2; for(int i=n-2;i>=0;i--) { if(x!=a[i])…