这是一题不太明显的动态规划,主要考察的应该是深度优先搜索. static LinkedList<String> list = new LinkedList<String>(); static ArrayList<String> res=new ArrayList<String>(); public ArrayList<String> wordBreak(String s, List<String> set) { list.clear(…

139. Word Break 字符串能否通过划分成词典中的一个或多个单词. 使用动态规划,dp[i]表示当前以第i个位置(在字符串中实际上是i-1)结尾的字符串能否划分成词典中的单词. j表示的是以当前i的位置往前找j个单词,如果在j个之前能正确分割,那只需判断当前这j单词能不能在词典中找到单词.j的个数不能超过词典最长单词的长度,且同时不能超过i的索引. 初始化时要初始化dp[0]为true,因为如果你找第一个刚好匹配成功的,你的dp[i - j]肯定就是dp[0].因为多申请了一个,所以d…

欢迎fork and star:Nowcoder-Repository-github 140. Word Break II 题目: Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, add spaces in s to construct a sentence where each word is a valid dictionary word. You may a…

题目描述 给定一个非空的字符串s,一个非空的字符串list作为字典.通过在s中添加空格可以将s变为由list中的word表示的句子,要求返回所有可能组成的句子.设定list中的word不重复,且每一个word都可以重复使用. 算法一 先来一个暴力的方法,如下图所示:1)用一个currStr记录当前句子,初始为“”,两个指针start.end分别表示当前词word的起始和结束:2)如果word在list中则将其加入currStr中,start = end +1,否则end后移:3)重复 2)操作直…

139. Word Break Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, determine if s can be segmented into a space-separated sequence of one or more dictionary words. You may assume the dictionary does not contain…

Given a string s and a dictionary of words dict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences. For example, given s = "catsanddog", dict = ["cat", "cats&quo…

Given a string s and a dictionary of words dict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences. For example, givens = "catsanddog",dict = ["cat", "cats"…

原题地址 动态规划题 令s[i..j]表示下标从i到j的子串,它的所有分割情况用words[i]表示 假设s[0..i]的所有分割情况words[i]已知.则s[0..i+1]的分割情况words[i+1] = words[k] + s[k+1..i+1],其中(有三个条件要满足)(1) 0 <= k <= i,(2) words[k]非空,(3) s[k+1..i+1]在字典中. 根据这个递推公式求解,有两种枚举方式: 1. 对于每个待求解的位置i,从0到i枚举所有的k,然后检验words[…

https://leetcode.com/problems/word-break/ Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words. For example, givens = "leetcode",dict = ["leet"…

题目: Given a string s and a dictionary of words dict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences. For example, givens = "catsanddog",dict = ["cat", "cats&q…