CSU-2046: sequence】的更多相关文章

题意:给n个数,m个询问.每个询问是一个区间,求区间内差的绝对值为1的数对数. 题解:先离散化,然后莫队算法.莫队是离线算法,先按按询问左端点排序,在按右端点排序. ps:第一次写莫队,表示挺简单的,不过这题之前乱搞一气一直TLE,莫队还是很强大的. 代码: #include <algorithm> #include <iostream> #include <cstdio> #include <cmath> #include <cstring>…
莫队算法+map #include<cstdio> #include<cstring> #include<cmath> #include<map> #include<algorithm> using namespace std; +; ],pos[maxn]; struct X { int l,r,id; } s[maxn]; int L,R; int Ans,f[maxn]; bool cmp(const X&a,const X&…
Inversion Sequence Problem's Link:   http://acm.csu.edu.cn/OnlineJudge/problem.php?id=1555 Mean: 给你一个序列a[n],要你按照要求去构造一个序列b. 序列a[i]表示序列b中的i前面有a[i]个数比i大. 转换一下就是: 已知一个连续的序列(1,2,3,4,...),然后告诉了我们这个序列中每个数前面比本身大的个数,根据这些条件将这个序列调整顺序,找到满足条件的序列. analyse: STL大法好…
Description For sequence i1, i2, i3, … , iN, we set aj to be the number of members in the sequence which are prior to j and greater to j at the same time. The sequence a1, a2, a3, … , aN is referred to as the inversion sequence of the original sequen…
题意:求三个序列的最长公共子序列. 思路:一开始以为只要求出前两个的LCS,然后和第三个再求一遍LCS就是答案了.但是样例就对我进行啪啪啪打脸了.实际上就跟两个序列的差不多,换成三维的就行了. 代码:需要注意的是max速度比较慢,最后改成if #include<stdio.h> #include<string.h> #include<iostream> using namespace std; ; int dp[N][N][N]; char a[N],b[N],c[N]…
Description 有一个1到N的自然数序列1,2,3,...,N-1,N. 我们对它进行M次操作,每次操作将其中连续的一段区间 [Ai,Bi][Ai,Bi] (即第Ai个元素到第Bi个元素之间的一段)取出,然后插入到剩下的第Ci个元素的后面,如果Ci=0,表示插入到最左端. 现在,M次操作完后,有K个询问,每个询问Pi表示询问最终第Pi个元素是几.你的任务是写一个程序,依次回答这K个询问. Input 第一行三个数,N,M,K. 接下来M行,每行三个整数Ai,Bi,Ci. 接下来K行,每行…
Parenthesis Problem Description: Bobo has a balanced parenthesis sequence P=p1 p2-pn of length n and q questions. The i-th question is whether P remains balanced after pai and pbi swapped. Note that questions are individual so that they have no affec…
题目连接 http://poj.org/problem?id=2046 Gap Description Let's play a card game called Gap. You have 28 cards labeled with two-digit numbers. The first digit (from 1 to 4) represents the suit of the card, and the second digit (from 1 to 7) represents the…
题目链接:http://acm.csu.edu.cn/csuoj/problemset/problem?pid=1809 Bobo has a balanced parenthesis sequence P=p 1 p 2…p n of length n and q questions. The i-th question is whether P remains balanced after p ai and p bi  swapped. Note that questions are ind…
1809: Parenthesis Submit Description Bobo has a balanced parenthesis sequence P=p1 p2…pn of length n and q questions. The i-th question is whether P remains balanced after pai and pbi  swapped. Note that questions are individual so that they have no…
题目链接:http://acm.csu.edu.cn/csuoj/problemset/problem?pid=1556 Description Jerry is caught by Tom. He was penned up in one room with a door, which only can be opened by its code. The code is the answer of the sum of the sequence of number written on th…
题目链接:http://acm.csu.edu.cn/csuoj/problemset/problem?pid=1553 Description Give you a sequence of n numbers, and a number k you should find the max length of Good subsequence. Good subsequence is a continuous subsequence of the given sequence and its m…
Improvise a Jazz Solo with an LSTM Network 实现使用LSTM生成音乐的模型,你可以在结束时听你自己的音乐,接下来你将会学习到: 使用LSTM生成音乐 使用深度学习生成你自己的爵士乐 现在加载库,其中,music21可能不在你的环境内,你需要在命令行中执行pip install msgpack以及pip install music21来获取. from __future__ import print_function import IPython impo…
oracle创建序列化: CREATE SEQUENCE seq_itv_collection            INCREMENT BY 1  -- 每次加几个              START WITH 1399       -- 从1开始计数              NOMAXVALUE        -- 不设置最大值              NOCYCLE               -- 一直累加,不循环              CACHE 10; oracle修改序列…
功能:备份存储过程,视图,函数触发器,Sequence序列号等准备工作:--1.创建文件夹 :'E:/OracleBackUp/ProcBack';--文本存放的路径--2.执行:create or replace directory MyProcBakPath as 'E:/OracleBackUp/ProcBack';--3.赋权限:sqlplus /nologconn user/pswd as sysdbagrant select on DBA_OBJECTS to user;--4.创建…
环境:Oracle 11.2.0.4 DG 故障现象: 客户在备库告警日志中发现GAP sequence提示信息: Mon Nov 21 09:53:29 2016 Media Recovery Waiting for thread 1 sequence 12034 Fetching gap sequence in thread 1, gap sequence 12034-12078 Mon Nov 21 09:55:20 2016 FAL[client]: Failed to request…
The set [1,2,3,-,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order,We get the following sequence (ie, for n = 3): "123" "132" "213" "231" "312" "3…
Check whether the original sequence org can be uniquely reconstructed from the sequences in seqs. The org sequence is a permutation of the integers from 1 to n, with 1 ≤ n ≤ 104. Reconstruction means building a shortest common supersequence of the se…
Given a binary tree, find the length of the longest consecutive sequence path. The path refers to any sequence of nodes from some starting node to any node in the tree along the parent-child connections. The longest consecutive path need to be from p…
Given an array of numbers, verify whether it is the correct preorder traversal sequence of a binary search tree. You may assume each number in the sequence is unique. Follow up: Could you do it using only constant space complexity? 这道题让给了我们一个一维数组,让我们…
Given an unsorted array of integers, find the length of the longest consecutive elements sequence. For example, Given [100, 4, 200, 1, 3, 2], The longest consecutive elements sequence is [1, 2, 3, 4]. Return its length: 4. Your algorithm should run i…
The set [1,2,3,…,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order,We get the following sequence (ie, for n = 3): "123" "132" "213" "231" "312" "3…
The set [1,2,3,-,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order,We get the following sequence (ie, for n = 3): "123" "132" "213" "231" "312" "3…
传送门 Description Chloe, the same as Vladik, is a competitive programmer. She didn't have any problems to get to the olympiad like Vladik, but she was confused by the task proposed on the olympiad. Let's consider the following algorithm of generating a…
传送门 NanoApe Loves Sequence Ⅱ Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 262144/131072 K (Java/Others)Total Submission(s): 1585    Accepted Submission(s): 688 Description NanoApe, the Retired Dog, has returned back to prepare for for the…
传送门 NanoApe Loves Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/131072 K (Java/Others) Total Submission(s): 1323    Accepted Submission(s): 521 Description NanoApe, the Retired Dog, has returned back to prepare for the Natio…
系列文章 [UML]UML系列——用例图Use Case [UML]UML系列——用例图中的各种关系(include.extend) [UML]UML系列——类图Class [UML]UML系列——类图class的关联关系(聚合.组合) [UML]UML系列——类图class的依赖关系 [UML]UML系列——类图class的泛化关系 [UML]UML系列——类图class的实现关系Realization [UML]UML系列——包图Package [UML]UML系列——活动图activity…
                                    Bracket Sequence Time Limit: 3000MS   Memory Limit: 65536KB   64bit IO Format: %lld & %llu [Submit]   [Go Back]   [Status] Description There is a sequence of brackets, which supports two kinds of operations.1. we c…
转载链接:http://www.cnblogs.com/zhangyoushugz/archive/2012/11/09/2762720.html 众所周知,在之前的sqlserver版本中,一般采用GUID或者identity来作为标示符,但是identity是一个表对象,只能保证在一张表里面的序列,当我们遇到以下情况时, 表1 ID 订单类型 价格 1 火车票 200 4 飞机票 2000 5 船票 600 表2 ID 订单类型 价格 2 酒店 400 3 公园门票 170 6 租车费用 3…
原题连接:https://www.patest.cn/contests/pat-a-practise/1051 题目: Given a stack which can keep M numbers at most. Push N numbers in the order of 1, 2, 3, ..., N and pop randomly. You are supposed to tell if a given sequence of numbers is a possible pop seq…