哈希 poj 3274】的更多相关文章

n个牛 二进制最多k位 给你n个数 求max(j-i)&&对应二进制位的和相同 7    1  1  1  倒的 6    0  1  1 7    1  1  1 2    0  1  0 1    1  0  0 4    0  0  1 2    0  1  0 3 4 5 6  加起来一样 前缀和 - 第一列 然后就发现对应相等就是和相同 根据 和  hash 和   有小于0的 下标注意一下 #include<stdio.h> #include<algorith…
http://poj.org/problem?id=3274 题意 :农夫约翰的n(1 <= N <= 100000)头奶牛,有很多相同之处,约翰已经将每一头奶牛的不同之处,归纳成了K种特性,比如1号特性代表它身上有斑点,2号特性代表它比较喜欢用passcal 写程序而不是C .约翰使用“特性标识符”来描述奶牛的各种特性,例如:一头奶牛的特性标识符是13,将13写成二进制1101,从右向左看,就表示这头奶牛具有1,3,4这三个特性,但没有2号特性,约翰把n头奶牛排成一排,发现在有些连续区间里的…
题目:http://poj.org/problem?id=3274 #include <iostream> #include<cstdio> #include<cstring> #include<cstdlib> #include<stack> #include<queue> #include<iomanip> #include<cmath> #include<map> #include<ve…
Gold Balanced Lineup Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 13540   Accepted: 3941 Description Farmer John's N cows (1 ≤ N ≤ 100,000) share many similarities. In fact, FJ has been able to narrow down the list of features shared…
Farmer John's N cows (1 ≤ N ≤ 100,000) share many similarities. In fact, FJ has been able to narrow down the list of features shared by his cows to a list of only K different features (1 ≤ K ≤ 30). For example, cows exhibiting feature #1 might have s…
题目链接:http://poj.org/problem?id=3274 题意+思路: 点击这里 补充:因为有减法运算,所以可能会造成运算后结果为负数,所以需要把结果统一转换成正数[不然数组下标访问不到负数位置],还有要先把0放入哈希表,不然会出现长度为1但是没有匹配的情况 比如:1 3   7 结果为1,如果没把0放进哈希表则结果为0 #include<iostream> #include<algorithm> #include<cstring> #include<…
相应POJ题目:点击打开链接 Snowflake Snow Snowflakes Time Limit: 4000MS   Memory Limit: 65536K Total Submissions: 33595   Accepted: 8811 Description You may have heard that no two snowflakes are alike. Your task is to write a program to determine whether this is…
Quicksum Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 16488   Accepted: 11453 Description A checksum is an algorithm that scans a packet of data and returns a single number. The idea is that if the packet is changed, the checksum will…
n个雪花 判断有没有相同的 正的和倒的相同都可以 哈希一下  比的少了就可以 #include<stdio.h> #include<algorithm> #include<string.h> #include<math.h> using namespace std; #define MAXN 15010 #define mod 14997 int cnt[MAXN]; struct node { ]; }x[MAXN][]; bool jud(node a,…
Gold Balanced Lineup Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 10924 Accepted: 3244 Description Farmer John's N cows (1 ≤ N ≤ 100,000) share many similarities. In fact, FJ has been able to narrow down the list of features shared by h…