网址:https://leetcode.com/problems/majority-element/ 参考:https://blog.csdn.net/u014248127/article/details/79230221 可以直接通过map解决 利用神奇的 摩尔投票算法( Boyer-Moore Voting Algorithm) 不断的消去两个不同的数,最后剩下的数肯定是所求的众数! 细节: 若第一个数的出现次数不止 1,则“消去”意味着次数-1 如果两数相同,要将此数的次数累加 class…

给定一个大小为 n 的数组,找到其中的众数.众数是指在数组中出现次数大于 ⌊ n/2 ⌋ 的元素.你可以假设数组是非空的,并且数组中的众数永远存在. 详见:https://leetcode.com/problems/majority-element/description/ Java实现: 方法一: class Solution { public int majorityElement(int[] nums) { int n=nums.length; if(n==0||nums==null){…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. Credits:Special thanks to @t…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 给定一个数组,求其中权制最大的元素,(该元素出现超过了一…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 题目标签:Array 忘记说了,特地回来补充,今天看完<…

169. Majority Element 求超过数组个数一半的数 可以使用hash解决,时间复杂度为O(n),但空间复杂度也为O(n) class Solution { public: int majorityElement(vector<int>& nums) { unordered_map<int,int> count; int n=nums.size(); ;i<n;i++){ ) return nums[i]; } ; } }; 使用投票法,时间复杂度为O(…

题目描述 给定一个大小为 n 的数组,找到其中的众数.众数是指在数组中出现次数大于 ⌊ n/2 ⌋ 的元素. 你可以假设数组是非空的,并且给定的数组总是存在众数. 示例 1: 输入: [3,2,3] 输出: 3 示例 2: 输入: [2,2,1,1,1,2,2] 输出: 2 思路 思路一: 利用哈希表的映射,储存数组中的数字以及它们出现的次数,当众数出现时,返回这个数字. 思路二: 因为众数是出现次数大于n/2的数字,所以排序之后中间的那个数字一定是众数.即nums[n/2]为众数.但是在计算比…

169. Majority Element Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 题目大意:…

169. Majority Element Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 思路1:ha…

169. Majority Element /** * @param {number[]} nums * @return {number} */ var majorityElement = function(nums) { var hash = {}; var y=-1,z; //注意这里的方括号,利用变量访问对象属性时要用方括号 for(var i=0;i<=nums.length-1;i++){ if(hash[nums[i]]){ hash[nums[i]]++; }else{ hash[…