On a staircase, the i-th step has some non-negative cost cost[i]assigned (0 indexed). Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach the top of the floor, and you can either start from the step wi…

On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach the top of the floor, and you can either start from the step w…

leetcode 746. Min Cost Climbing Stairs(easy understanding dp solution) On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Once you pay the cost, you can either climb one or two steps. You need to find minimum cost…

problem 746. Min Cost Climbing Stairs 题意: solution1:动态规划: 定义一个一维的dp数组,其中dp[i]表示爬到第i层的最小cost,然后来想dp[i]如何推导.思考一下如何才能到第i层呢?是不是只有两种可能性,一个是从第i-2层上直接跳上来,一个是从第i-1层上跳上来.不会再有别的方法,所以dp[i]只和前两层有关系,所以可以写做如下: dp[i] = min(dp[i- 2] + cost[i - 2], dp[i - 1] + cost[i…

lc 746 Min Cost Climbing Stairs 746 Min Cost Climbing Stairs On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach t…

On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach the top of the floor, and you can either start from the step w…

题目翻译 有一个楼梯,第i阶用cost[i](非负)表示成本.现在你需要支付这些成本,可以一次走两阶也可以走一阶. 问从地面或者第一阶出发,怎么走成本最小. 测试样例 Input: cost = [10, 15, 20] Output: 15 Explanation: 从第一阶出发,一次走两步 Input: cost = [1, 100, 1, 1, 1, 100, 1, 1, 100, 1] Output: 6 Explanation: 从地面出发,走两步,走两步,走两步,走一步,走两步,走一…

On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach the top of the floor, and you can either start from the step w…

On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach the top of the floor, and you can either start from the step w…

思路:动态规划. class Solution { //不能对cost数组进行写操作,因为JAVA中参数是引用 public int minCostClimbingStairs(int[] cost) { int cost_0 = cost[0], cost_1 = cost[1]; for(int i = 2; i < cost.length; i++) { int cost_2 = Math.min(cost_0, cost_1) + cost[i]; cost_0 = cost_1; co…