You are in this GAME. A critical mission, and you are surrounded by the beauties, ready to shed their slik gowns on your beck. On onside your feelings are pulling you apart and another side you are called by the duty. The biggiest question is seX OR…

Now you are one step away from knowing who is that WARRIOR. The Fighter who will decide the fate of war between the 2 countries. The Pride of One and Envey of the Other... You have got the secrete file which has the crucial information to identify th…

He is influential, he is powerful. He is your next contact you can get you out of this situation. You must reach him soon. Who is he? The few pointers intrecpted by KGB are in the file. Once we know him, we can find his most valuable possession, his…

After entring the luxurious condomium,you get the feel that you are in home of a yester Star. the extravagant flooring and furnishings shows the richness of this star. But where is she? There she is, lying peacefuly on her couch. See what Envy has do…

Some one was here, some one had breached the security and had infiltrated here. All the evidences are touched, Logs are altered, records are modified with key as a text from book.The Operation was as smooth as CAESAR had Conquested Gaul. After analys…

Dont blink your Eyes, you might miss it. But the fatigue and exhaustion rules out any logic, any will to stay awake. What you need now is a slumber. Cat nap will not do. 1 is LIFE and 0 is DEAD. in this GAME OF LIFE sleep is as important food. So...…

Your simple good Deeds can save you but your GREED can kill you. This has happened before. This greedy person lived a miserable life just for the greed of gold and lust. You must know him, once you know him, you must reach his capital and next clues…

So you reached Delhi and now the noise in your head is not allowing you to think rationally. The Nosise in your head has origin its Origin in your Stomach. And this is a big hunger. You can finish one or probably 2 Tandoori Chicken. So where can you…

摘要: 详解原型污染. 原文:Lodash 严重安全漏洞背后 你不得不知道的 JavaScript 知识 作者:Lucas HC Fundebug经授权转载,版权归原作者所有. 可能有信息敏感的同学已经了解到:Lodash 库爆出严重安全漏洞,波及 400万+ 项目.这个漏洞使得 lodash "连夜"发版以解决潜在问题,并强烈建议开发者升级版本. 我们在忙着"看热闹"或者""升级版本"的同时,静下心来想:真的有理解这个漏洞产生的原因,…

A Boring Question Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 156    Accepted Submission(s): 72 Problem Description       Input   The first line of the input contains the only integer T,(1≤T…

A Boring Question Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 487    Accepted Submission(s): 271 Problem Description There are an equation.∑0≤k1,k2,⋯km≤n∏1⩽j<m(kj+1kj)%1000000007=? We define…

/* 对于题目多读几遍,然后再关键字排序的时候,把对应的数组序号也排序, EYDE    MBLR    THAN    MEKT    ETOE    EOTH        MEETME    BYTHEO    LDOAKT    REENTH */ #include<iostream>#include<string>#include<algorithm>using namespace std;int main(){ int n; string keyword; …

Still Hungry and unsutisfied, you are looking for more. Some more, unique un heard dishes. Then you can find one to make it your self. Its his Dish. He has his own website which is he describes as " a social home for each of our passions". The l…

写在前面 本章节写得差不多了,不过还需要再整理一下(TODO). hash例子 hash.digest([encoding]):计算摘要.encoding可以是hex.latin1或者base64.如果声明了encoding,那么返回字符串.否则,返回Buffer实例.注意,调用hash.digest()后,hash对象就作废了,再次调用就会出错. hash.update(data[, input_encoding]):input_encoding可以是utf8.ascii或者latin1.如果…

二,RoundC import java.io.BufferedReader; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.FileOutputStream; import java.io.InputStreamReader; import java.io.PrintStream; import java.util.ArrayList; import java.util.…

To get an idea of what all of this stuff “does,” let me start off with an update on the average day at Stack Overflow. So you can compare to theprevious numbers from November 2013, here’s a day of statistics from February 9th, 2016 with differences s…

5/12 2016 Multi-University Training Contest 6 官方题解 打表找规律/推公式 A A Boring Question(BH) 题意: ,意思就是在[0,n]里选择m个数字的相邻数字二项式组合的积的总和. 思路: 想了好久,不会,但是这题有300多人过,怀疑人生... 打了个表: n=0, m=2, ans=1n=1, m=2, ans=3n=2, m=2, ans=7n=3, m=2, ans=15n=4, m=2, ans=31n=5, m=2, a…

转自:http://blog.evjang.com/2017/01/nips2016.html           Eric Jang Technology, A.I., Careers               Monday, January 2, 2017 Summary of NIPS 2016   The 30th annual Neural Information Processing Systems (NIPS) conference took place in Barcelona…

The major advancements in Deep Learning in 2016 Pablo Tue, Dec 6, 2016 in MACHINE LEARNING DEEP LEARNING GAN Deep Learning has been the core topic in the Machine Learning community the last couple of years and 2016 was not the exception. In this arti…

前言: 好吧我承认已经有四年多没有更新博客了.... 在这四年中发生了很多事情,换了工作,换了工作的方向.在工作的第一年的时候接触机器学习,从那之后的一年非常狂热的学习机器学习的相关技术,也写了一些自己的理解和感悟.今天大概看了一下这个博客的总体阅读人数已经有70多万了,印象中之前还只有十多二十万.很高兴这些文章能够帮助你更好的理解一些机器学习相关的基础知识,非常感谢各位读者和爬虫机器人(:-p)的支持! 后来个人选择将工作的方向从机器学习换到了Hadoop相关领域,中间有很多感悟我想之后再单独…

P6 EPPM Installation and Configuration Guide 16 R1         April 2016 Contents About Installing and Configuring P6 EPPM ........................................................ 6 Prerequisites for P6 EPPM Configuration ...............................…

09.00 – 09.45 hrs Tracks Cloud, Mobile, & IoT Security    A New Security Paradigm for IoT (Internet of Threats) Hadi Nahari, Founder, R62 Security Computing has changed since the 50s except for security; nowhere is this more apparent than in the IoT.…

前言:本次尝试源于我们内部的一个项目,由于前端逻辑比较复杂,就打算将前后端分开来开发.由于之前用Django开发过软件,对Angular.js(Angular 1.0版)也有一定的了解,因此就将技术路线锁定在了这两个开源工具上,用Angular做前端,Django做后端. 前后端的关系 前后端是否分离是我们设计网站应用程序架构时需要想清楚的首要问题.这直接影响了我们的开发流程,技术路线,甚至后期的维护. 要搞清楚是否需要分离,首先要明白前后端各自最主要的职责是什么. 关于前端 之所以叫做前端,是…

Csdn /Tamic 原文地址: http://blog.csdn.net/sk719887916/article/details/53525067 本文章6月份已完成(http://www.jianshu.com/p/8ed9543b15db),已被多个公司或个人公众号邀稿推送 纵观移动开发 , 新技术出现层出不穷,除了第三方开源个人的一些技术分享,主要还是谷歌,FaceBook,Square这种驱动型技术公司的技术驱动引领,也有国内阿里,百度,携程的基于国外框架拓展的一些主流框架推出,其实…

ROSCon 2016视频和幻灯片发布 By Tully Foote on 十月19,2016 7:28 AM 全部PPT下载地址:http://pan.baidu.com/s/1gf2sn2F ROSCon在各方面都创下了历史新高,超过450名与会者,比去年的赞助增加了60%. 感谢大家来和你的支持! 并感谢我们的赞助商的财务支持,使会议成长! 我们很高兴地宣布,我们已经发布了关于该计划的所有会谈的录音. 你可以找到它们链接到: http://roscon.ros.org/2016/#prog…

A.2016 给出正整数 n 和 m,统计满足以下条件的正整数对 (a,b) 的数量: 1. 1≤a≤n,1≤b≤m; 2. a×b 是 2016 的倍数. Input   输入包含不超过 30 组数据. 每组数据包含两个整数 n,m (1≤n,m≤10 9).   Output对于每组数据,输出一个整数表示满足条件的数量.Sample Input 32 63 2016 2016 1000000000 1000000000 Sample Output 1 30576 75231468955026…

1.解决了ScrollView滑动冲突问题. 2.设置好了“查看详解”与“题目编号”的部分. 3.完成了app启动图片的设置,并在启动的过程中开辟新的线程连接服务器并开启监听数据. 别忘了注册启动Activity,并设置为app启动项. 参考:http://www.iteye.com/problems/62343  http://www.cnblogs.com/mybkn/archive/2012/07/18/2597347.html 4.mCsv.setEnabled(true);设置是否可以…

Hierarchical Question-Image Co-Attention for Visual Question Answering NIPS 2016 Paper: https://arxiv.org/pdf/1606.00061.pdf Code: https://github.com/jiasenlu/HieCoAttenVQA Related Blog: [AI前沿]机器阅读理解与问答·Dynamic Co-Attention Networks Introduction: 本文提…

百练 / 2016计算机学科夏令营上机考试 已经结束 题目 排名 状态 统计 提问   A:分段函数 查看 提交 统计 提问 总时间限制:  1000ms 内存限制:  65536kB 描述 编写程序,计算下列分段函数y=f(x)的值. y=-x+2.5; 0 <= x < 5 y=2-1.5(x-3)(x-3); 5 <= x < 10 y=x/2-1.5; 10 <= x < 20 输入 一个浮点数N,0 <= N < 20 输出 输出N对应的分段函数值…

def 程序员 原文 https://www.zhihu.com/question/54350343 陈硕 等 54 人赞同了该回答 1 知乎 陈硕大牛的 服务器多线程编程muduo 输的好不好可能更多的在于适合不适合 尤其是技术书籍 如果你已经具有C++基础 对野指针和内存泄漏有自己的心得和疑惑 如果你已经具有网络编程基础 对实战服务器有着进一步了解的想法 这本书真的不错 2 深入应用c++11代码优化与工程级应用 这本书其实是在看第一本遇到坎,然后学习C++11 买的. 结果坑不一定比第一本…