Given a collection of intervals, merge all overlapping intervals. For example, Given [1,3],[2,6],[8,10],[15,18], return [1,6],[8,10],[15,18]. 这道和之前那道Insert Interval 插入区间 很类似,这次题目要求我们合并区间,之前那题明确了输入区间集是有序的,而这题没有,所有我们首先要做的就是给区间集排序,由于我们要排序的是个结构体,所以我们要定义自…

Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 题目的意思是将相交得区间合并,典型的贪心算法 首先将区间先按照start进行排序, 然后保存先前区间的start和end 如果当前的start > 先前的end,说明当前的区间与之前的区间不想交,则将先前的区间放入结果中…

Merge Intervals Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18].     先排序,然后循环合并   /** * Definition for an interval. * struct Interval { * int start; * int end;…

Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 思路:开始想用线段树,后来想想这个不是动态变化的没必要. 按区间的第一个值从小到大排序,然后跳过后面被覆盖的区间来找. sort折腾了好久,开始搞不定只好自己写了一个归并排序.现在代码里的sort是可用的. class…

题目要求: Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 解题思路: 1)将集合进行排序: 集合的排序建议使用Collections的sort方法实现,需要自己实现Comparator接口: 2)依次进行归并,当后者的start大于当前Interval的end时,将…

Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 区间合并,分为三种情况 /** * Definition for an interval. * struct Interval { * int start; * int end; * Interval() : start…

Insert Interval Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Given intervals [1,3],[6,9], i…

Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 解题思路: 1.将区间按照起始位置从小到大排序: 2.一次遍历,如果发现当前区间起始小于上一个区间结束,则进行合并: 解题步骤: 1.因为需要比较结构体,所以编写比较函数< 2.新建一个结果数组,保存合并后的结果: 3.…

Given a collection of intervals, merge all overlapping intervals. For example, Given [1,3],[2,6],[8,10],[15,18], return [1,6],[8,10],[15,18]. 解题思路一: 用两个指针startIndex和endIndex来维护每次添加intervals的start和end的位置,然后分类讨论即可,JAVA实现如下: public List<Interval> merge…

题目来源 https://leetcode.com/problems/merge-intervals/ Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 题意分析 Input:a list of intervals Output:a list of intervals…