Given k strings, find the longest common prefix (LCP). Have you met this question in a real interview?     Example For strings "ABCD", "ABEF" and "ACEF", the LCP is "A" For strings "ABCDEFG", "ABCEFG&…

Write a function to find the longest common prefix string amongst an array of strings. 这道题让我们求一系列字符串的共同前缀,没有什么特别的技巧,无脑查找即可,我们定义两个变量i和j,其中i是遍历搜索字符串中的字符,j是遍历字符串集中的每个字符串.这里将单词上下排好,则相当于一个各行长度有可能不相等的二维数组,我们遍历顺序和一般的横向逐行遍历不同,而是采用纵向逐列遍历,在遍历的过程中,如果某一行没有了,说明其为…

Write a function to find the longest common prefix string amongst an array of strings. If there is no common prefix, return an empty string "". Example 1: Input: ["flower","flow","flight"] Output: "fl" Exa…

Write a function to find the longest common prefix string amongst an array of strings. If there is no common prefix, return an empty string "". Example 1: Input: ["flower","flow","flight"] Output: "fl" Exa…

公众号:爱写bug Write a function to find the longest common prefix string amongst an array of strings. If there is no common prefix, return an empty string "". 编写一个函数来查找字符串数组中的最长公共前缀. 如果不存在公共前缀,返回空字符串 "". Example 1: Input: ["flower"…

1. 题目 1.1 英文题目 Write a function to find the longest common prefix string amongst an array of strings. If there is no common prefix, return an empty string "". 1.2 中文题目 编写一个函数来查找字符串数组中的最长公共前缀. 如果不存在公共前缀,返回空字符串 "". 1.3输入输出 输入 输出 strs = […

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 个人公众号:负雪明烛 本文关键词:prefix, 公共前缀,题解,leetcode, 力扣,Python, C++, Java 目录 题目描述 题目大意 解题方法 遍历前缀子串 使用set 遍历最短字符串 排序 日期 题目地址:https://leetcode.com/problems/longest-common-prefix/description/ 题目描述 Write a fun…

Write a function to find the longest common prefix string amongst an array of strings. If there is no common prefix, return an empty string "". Example 1: Input: ["flower","flow","flight"] Output: "fl" Exa…

问题:链接 Write a function to find the longest common prefix string amongst an array of strings. 解答: 注意 当传入參数为空,即vector<string> 大小为0时.应该直接返回一个空字符串"".而不是返回NULL. 这点须要特别注意. 代码: class Solution { public: string longestCommonPrefix(vector<string&…

题意:给多个字符串,返回这些字符串的最长公共前缀. 思路:直接逐个统计同一个位置上的字符有多少种,如果只有1种,那么就是该位是相同的,进入下一位比较.否则终止比较,返回前缀.可能有一个字符串会比较短,所以前缀最长也只是最短字符串的长度. class Solution { public: string longestCommonPrefix(vector<string>& strs) { string ans=""; if(strs.empty()) return a…