345. 反转字符串中的元音字母 编写一个函数,以字符串作为输入,反转该字符串中的元音字母. 示例 1: 输入: "hello" 输出: "holle" 示例 2: 输入: "leetcode" 输出: "leotcede" 说明: 元音字母不包含字母"y". class Solution { public String reverseVowels(String s) { if (s.length() ==…

Write a function that takes a string as input and reverse only the vowels(元音字母) of a string. Example 1:Given s = "hello", return "holle". Example 2:Given s = "leetcode", return "leotcede". Note:The vowels does not i…

题目描述: Write a function that takes a string as input and reverse only the vowels of a string. Example 1:Given s = "hello", return "holle". Example 2:Given s = "leetcode", return "leotcede". Note:The vowels does not i…

Reverse Vowels of a String Write a function that takes a string as input and reverse only the vowels of a string. Example 1: Given s = "hello", return "holle". Example 2: Given s = "leetcode", return "leotcede". /**…

编写一个函数,以字符串作为输入,反转该字符串中的元音字母. 示例 1: 输入: "hello" 输出: "holle" 示例 2: 输入: "leetcode" 输出: "leotcede" 说明: 元音字母不包含字母"y". 思路 设立2个指针,一个从索引0开始向右,一个从末尾向前,根据条件进行处理即可 代码 class Solution: def reverseVowels(self, s): &quo…

Write a function that takes a string as input and reverse only the vowels of a string. Example 1: Input: "hello" Output: "holle" Example 2: Input: "leetcode" Output: "leotcede" Note:The vowels does not include the l…

题意:给定一个字符串,反转字符串中的元音字母. 例如: Input: "leetcode" Output: "leotcede" 法一:双指针 class Solution { public: string reverseVowels(string s) { if(s == "") return ""; set <char> st ={'a','e','i','o','u','A','E','I','O','U'}…

题意:倒置字符串中的元音字母. 用两个下标分别指向前后两个相对的元音字母,然后交换. 注意:元音字母是aeiouAEIOU. class Solution { public: bool isVowels(char c){ string Vowels = "aeiouAEIOU"; ; i < Vowels.size(); ++i){ if(c == Vowels[i]) return true; } return false; } string reverseVowels(str…

两个for 第一个for将每一个元音依次存放进一个char数组 第二个for,每检测到元音,就从char数尾部开始,依次赋值 如何检测元音呢?当然写一个冗长的if(),不过我们有更好的选择 hashset的contains, 或者String自带的contains, 或者建一个int[128],因为元音有5个,算上大小写,一共10个,他们的ascii值都在128以内,然后将元音对应的int[]值设为1,其它设为0,只要检测int[strs[i]] ?= 0即可判断是否为元音 class Solu…

题意:判断字符串是否是回文字符串 先将所有的字母和数字字符保留,并将大写字母转化成小写字母,然后将字符串倒置,比较前后两个字符串是否相同. 该题最好的解法可以模仿 Leetcode 345 Reverse Vowels of a String 字符串处理 class Solution { public: bool isPalindrome(string s) { ; ; i< s.size(); ++i){ if(isalpha(s[i]) || isdigit(s[i])) { if(isup…