动态规划:多阶段决策问题,每步求解的问题是后面阶段问题求解的子问题,每步决策将依赖于以前步骤的决策结果.(可以用于组合优化问题) 优化原则:一个最优决策序列的任何子序列本身一定是相当于子序列初始和结束状态的最优决策序列. 只有满足优化原则的问题才可以利用动态算法进行求解,因为只有全局最优解法等于其每个子问题的最优才可以分阶段进行求解. The cows don't use actual bowling balls when they go bowling. They each take a nu…
题目链接:http://poj.org/problem?id=3176 思路分析:基本的DP题目:将每个节点视为一个状态,记为B[i][j], 状态转移方程为 B[i][j] = A[i][j] + Max( B[i+1][j], B[i+1][j+1] ); 代码如下: #include <stdio.h> + ; int A[MAX_N][MAX_N], B[MAX_N][MAX_N]; int Max( int a, int b ) { return a > b ? a : b;…
Software Company Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 1112 Accepted: 482 Description A software developing company has been assigned two programming projects. As both projects are within the same contract, both must be hande…
Cow Bowling Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 13016 Accepted: 8598 Description The cows don't use actual bowling balls when they go bowling. They each take a number (in the range 0..99), though, and line up in a standard…
Cow Bowling Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 16448 Accepted: 10957 Description The cows don't use actual bowling balls when they go bowling. They each take a number (in the range 0..99), though, and line up in a standard bow…
Description Given a two-dimensional array of positive and negative integers, a sub-rectangle is any contiguous sub-array of size 1*1 or greater located within the whole array. The sum of a rectangle is the sum of all the elements in that rectangle. I…
题 Description The cows don't use actual bowling balls when they go bowling. They each take a number (in the range 0..99), though, and line up in a standard bowling-pin-like triangle like this: 7 3 8 8 1 0 2 7 4 4 4 5 2 6 5 Then the other cows travers…
北大教你怎么打保龄球 题目很简单的,我就不翻译了,简单来说就是储存每一行的总数,类似于状态压缩 #include <stdio.h> #include <stdlib.h> #define MAX(a,b) a>b?a:b ][]; void Search(const int); int main(void) { int N, i, line; while (~scanf("%d", &N)) { Cow_Map[][] = ; ; line &l…
