A计划 Time Limit : 3000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 76   Accepted Submission(s) : 37 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description 可怜的公主在一次次被魔王掳走一次次被骑士们救回来之后,而今,不幸的…
Pretty Poem Time Limit: 2 Seconds     Memory Limit:65536 KB Poetry is a form of literature that uses aesthetic and rhythmic qualities of language. There are many famous poets in the contemporary era. It is said that a few ACM-ICPC contestants can eve…
IIS上在主站点下搭建虚拟目录后,子站点中的<system.web>节点与主站点的<system.web>冲突解决方法: 在主站点的<system.web>上一级添加父节点: <location path="." allowOverride="false" inheritInChildApplications="false">     <system.web>         <!…
哈密顿绕行世界问题 Time Limit : 3000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 66   Accepted Submission(s) : 33 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description 一个规则的实心十二面体,它的 20个顶点标出世界著名的…
以下程序在hadoop1.2.1上测试成功. 本例先将源代码呈现,然后详细说明执行步骤,最后对源代码及执行过程进行分析. 一.源代码 package org.jediael.hadoopdemo.wordcount; import java.io.IOException; import java.util.StringTokenizer; import org.apache.hadoop.conf.Configuration; import org.apache.hadoop.fs.Path;…
Tautology Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 10428   Accepted: 3959 Description WFF 'N PROOF is a logic game played with dice. Each die has six faces representing some subset of the possible symbols K, A, N, C, E, p, q, r, s…
人的视觉系统具有颜色恒常性,能从变化的光照环境和成像条件下获取物体表面颜色的不变特性,但成像设备不具有这样的调节功能, 不同的光照环境会导致采集的图像颜色与真实颜色存在一定程度的偏差,需要选择合适的颜色平衡(校正)算法,消除光照环境对颜 色显现的影响.灰度世界算法是最常用平衡算法. 一.灰度世界算法 灰度世界算法以灰度世界假设为基础,该假设认为:对于一幅有着大量色彩变化的图像,,三个分量的平均值趋于同一灰 度值.从物理意义上讲,灰色世界法假设自然界景物对于光线的平均反射的均值在总体上是个定值,这…
我们知道通过Sql代理,可以实现数据库的定时备份功能:当数据库里的数据库很多时,备份一个数据库需要建立对应的定时作业,相对来说比较麻烦: 还好,微软自带的osql工具,比较实用,通过在命令行里里输入命令,也能实现数据库备份的功能:如果能通过sql语句来生成一个批处理文件,那就方便了: 下面即是生成批处理文件的sql脚本,通过它可以实现:运行一个批处理文件,备份数据库服务器上的所有数据库到指定目录. 生成批量备份脚本: /**************************************…
一.什么是正则表达式 正则表达式,又称正规表示法,是对字符串操作的一种逻辑公式.正则表达式可以检测给定的字符串是否符合我们定义的逻辑,也可以从字符串中获取我们想要的特定部分.它可以迅速地用极简单的方式达到字符串的复杂控制. 二.正则表达式的语法 看一个过滤纯数字的例子 - (BOOL)validateNumber:(NSString *) textString { NSString* number=@"^[0-9]+$"; NSPredicate *numberPre = [NSPre…
//初始化textfield并设置位置及大小   UITextField *text = [[UITextField alloc]initWithFrame:CGRectMake(20, 20, 130, 30)];   //设置边框样式,只有设置了才会显示边框样式   text.borderStyle = UITextBorderStyleRoundedRect; typedef enum {     UITextBorderStyleNone,      UITextBorderStyleL…
May Day Holiday Time Limit: 2 Seconds Memory Limit: 65536 KB As a university advocating self-learning and work-rest balance, Marjar University has so many days of rest, including holidays and weekends. Each weekend, which consists of Saturday and Sun…
Lunch Time Time Limit: 2 Seconds Memory Limit: 65536 KB The 999th Zhejiang Provincial Collegiate Programming Contest will be held in Marjar University. The canteen of Marjar University is making preparations for this grand competition. The canteen pr…
FatMouse' Trade Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 42953    Accepted Submission(s): 14336 Problem Description FatMouse prepared M pounds of cat food, ready to trade with the cats g…
加载bcmdhd模块:# modprobe bcmdhd 如果你希望开启 AP 模式,那么:# modprobe bcmdhd op_mode=2 在/etc/modules文件内添加bcmdhd op_mode=2,以实现bcmdhd模块的开机自动加载. hostapd安装与配置 参考链接:http://wireless.kernel.org/en/users/Documentation/hostapd#Using_your_distributions_hostapd 安装hostapd: 1…
一.JSON简介 JSON(JavaScript Object Notation,JavaScript对象表示法)是一种轻量级的数据交换格式. JSON是"名值对"的集合.结构由大括号'{}',中括号'[]',逗号',',冒号':',双引号'""'组成,包含的数据类型有Object,Number,Boolean,String,Array, NULL等. JSON具有以下的形式: 对象(Object)是一个无序的"名值对"集合,一个对象以"…
Human Gene Functions Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3103    Accepted Submission(s): 1761 Problem Description It is well known that a human gene can be considered as a sequence,…
Knight Moves Problem Description A friend of you is doing research on the Traveling Knight Problem (TKP) where you are to find the shortest closed tour of knight moves that visits each square of a given set of n squares on a chessboard exactly once.…
4270: 同源数 Time Limit: 3 Sec  Memory Limit: 128 MB Submit: 1284  Solved: 224 Description 如果x和y的质因子集合完全相同,那么我们就说他们是同源的. 比如说18 = 2 * 32,12 = 3 * 22: Input 本题有多组数据(组数 <= 555555). 每组数据输入形如: x y x, y为整数(1 <= x, y <= 1e18) Output 输出形入: ans 如果x, y为同源数,那么…
nutch将从网页中抓取到的信息放入hbase数据库中,默认情况下表名为$crawlId_webpage,但表中的内容以16进制进行表示,直接scan或者通过Java API进行读取均只能读取到16进制信息.     因此nutch提供了readdb选项进行数据获取,将表中的内容读取到一个文本中.  具体用法为: $ bin/nutch readdb Usage: WebTableReader (-stats | -url [url] | -dump <out_dir> [-regex reg…
参考自Google官方文档Traning/Getting Started/Building a simple user interface, Startinganother activity,http://developer.android.com/training/basics/firstapp/building-ui.html 1.创建主Activity 使用Eclipse新建项目MyFirstApp,UI布局如下: <LinearLayout xmlns:android="http:…
To Check current users permissions using Ecmascript\Javascript client object model SharePoint 2010. function checkifUserHasEditPermissions() { context = new SP.ClientContext.get_current(); web = context.get_web(); this._currentUser = web.get_currentU…
If you understand the comments below, never will you make mistakes with binary search! thanks to A simple CPP solution with lower_bound and C++ O(logn) Binary Search that handles duplicate, thanks to phu1ku 's answer on the second post. http://en.cpp…
reference: Rabin-Karp and Knuth-Morris-Pratt Algorithms By TheLlama– TopCoder Member https://www.topcoder.com/community/data-science/data-science-tutorials/introduction-to-string-searching-algorithms/ // to be improved #include <cstdio> #include <…
实现代码: $.extend($.fn.tabs.methods, { /** * 绑定双击事件 * @param {Object} jq * @param {Object} caller 绑定的事件处理程序 */ bindDblclick: function(jq, caller){ return jq.each(function(){ var that = this; $(this).children("div.tabs-header").find("ul.tabs&qu…
一个原则是:应该尽量少的使用parallelfor, 因为parallel for也需要时间开销.即: (1)如果外层循环次数远远小于内层循环次数,内层循环较多时,将parallel for加在内层循环. 示例代码: int a=0; int b=0; inline void openmpTest2(int thread_num) { for(int i=0;i<100;i++) { #pragma omp parallel for num_threads(thread_num) for(int…
1.       问题 C++如何实现不能被继承的类,即终结类.Java中有final关键字修饰,C#中有sealed关键字修饰,而C++目前还没有类似的关键字来修饰类实现终结类,需编程人员手动实现.   2.       解决方法 基本思路:由于任何派生类的对象在创建的时候,都必需在派生类的构造函数中调用父类的构造函数.所以,只要类的构造函数在子类中无法被访问,那么就阻止了该类被继承,实现终结类. 如果将一个类的构造函数声明为私有(private),可以阻止该类进一步派生,但是该类也无法直接实…
Dungeon Master Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 20995 Accepted: 8150 Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled wit…
Black Box Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 8754 Accepted: 3599 Description Our Black Box represents a primitive database. It can save an integer array and has a special i variable. At the initial moment Black Box is empty an…
Integration of Polynomial Time Limit: 2000/1000MS (Java/Others) Memory Limit: 128000/64000KB (Java/Others) Submit Statistic Next Problem Problem Description Suppose there are a polynomial which has n nonzero terms, please print the integration polyno…
Demacia of the Ancients Time Limit: 2 Seconds Memory Limit: 65536 KB There is a popular multiplayer online battle arena game called Demacia of the Ancients. There are lots of professional teams playing this game. A team will be approved as Level K if…