https://codeforces.com/gym/101810 A. Careful Thief time limit per test 2.5 s memory limit per test 256 MB input standard input output standard output There are consecutive buildings numbered from 1 to 109 each of which has an amount of money in it. T…

题意:有\(n\)个点,\(n-1\)条边,每条边正向和反向有两个权值,且每条边最多只能走两次,有\(m\)次询问,问你从\(u\)走到\(v\)的最大权值是多少. 题解:可以先在纸上画一画,不难发现,除了从\(u\)走到\(v\)的路径上的反向权值我们取不到,其他所有边的正反权值均能取到,所以答案就是:\(sum-u->v路径的反向权值\),问题也就转换成了求\(v->u\)的权值,那么这里我们就可以用LCA来求了. 首先,令一个点为根节点,然后求出\(v\)到根节点的距离和根节点到\(u\…

ACM International Collegiate Programming Contest World Finals 2014 A - Baggage 题目描述:有\(2n\)个字符摆在编号为\(1\)~\(2n\)格子里,奇数位为\(B\),偶数位为\(A\),另外编号为\((-2n+1)\)~\(0\)的格子是空的,现在可以移动两个相邻的字符,移动到两个空的格子里,最终使得全部\(A\)在全部\(B\)的左边,而且字符都是连续的,但不必放回原位,输出最小步数的方案. solution…

ACM International Collegiate Programming Contest World Finals 2013 A - Self-Assembly 题目描述:给出\(n\)个正方形组件,正方形每条边有一个标签,标签可能是00,表示这条边不能与其它边相拼,也可能是一个字母加正号或负号,相同字母不同符号的边可以相拼.每个组件有无限个,问利用这些组件是否能拼出一个无限大的多边形. solution 拆点,每个正方形拆成\(4\)个点,每条边一个,然后每条边拆成两个点(出点和入点)…

ACM International Collegiate Programming Contest, Tishreen Collegiate Programming Contest (2018) Syria, Lattakia, Tishreen University, April, 30, 2018 Problem A. Can Shahhoud Solve it? Problem B. Defeat the Monsters Problem C. UCL Game Night Problem…

ACM International Collegiate Programming Contest, Tishreen Collegiate Programming Contest (2017)- K. Poor Ramzi -dp+记忆化搜索 [Problem Description] 给你一串\(01\)字符串,将其划分,使得划分后,分别求出每组\(01\)之和后是回文的,求划分的方案数, [Solution] 定义\(dp[l][r]\)表示,区间\([l,r]\)中满足条件的方案数是多少.…

Solved A Gym 100712A Who Is The Winner Solved B Gym 100712B Rock-Paper-Scissors Solved C Gym 100712C Street Lamps Solved D Gym 100712D Alternating Strings Solved E Gym 100712E Epic Professor Solved F Gym 100712F Travelling Salesman Solved G Gym 10071…

IEEE/ACM International Conference on Advances in Social Network Analysis and Mining (ASONAM) 2014 Industry Track Call for Papers * Apologies if you received multiple copies of this CFP * Beijing China August 17-20, 2014Home Page: www.asonam2014.org F…

IEEE/ACM International Conference on Advances in Social Network Analysis and Mining (ASONAM) 2014 Industry Track Call for Papers Beijing China August 17-20, 2014Home Page: www.asonam2014.org Full paper/short paper/extended abstract submission deadlin…

2017 ACM - ICPC Asia Ho Chi Minh City Regional Contest A - Arranging Wine 题目描述:有\(R\)个红箱和\(W\)个白箱,将这些箱子分成若干堆,使得每一堆只有一种颜色,然后将这些堆排成一排,使得相邻的堆的颜色不一样,并且每堆红箱的个数不能超过\(d\),问有多少种方案. solution 不会. B - Barcode 题目描述:有一排\(n\)个球,现在要给这\(n\)个球涂成红色或蓝色,使得红色球的个数等于蓝色球的个数…