链接:http://acm.hdu.edu.cn/showproblem.php?pid=4969 Just a Joke Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 332    Accepted Submission(s): 135 Problem Description Here is just a joke, and do…

B. Spongebob and Joke Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/599/problem/B Description While Patrick was gone shopping, Spongebob decided to play a little trick on his friend. The naughty Sponge browsed through Pat…

B. Spongebob and Joke time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output While Patrick was gone shopping, Spongebob decided to play a little trick on his friend. The naughty Sponge browsed th…

B. Spongebob and Joke time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output While Patrick was gone shopping, Spongebob decided to play a little trick on his friend. The naughty Sponge browsed th…

Problem J. Joke 题目连接: http://codeforces.com/gym/100714 Description The problem is to cut the largest possible number of circles with diameter y out of a stripe of length x and width y. Input The only line of input consists of two positive real number…

B. Spongebob and Joke time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output While Patrick was gone shopping, Spongebob decided to play a little trick on his friend. The naughty Sponge browsed th…

题目链接:http://acm.hnu.cn/online/?action=problem&type=show&id=13341&courseid=0 Joke with permutation Time Limit: 3000ms, Special Time Limit:7500ms, Memory Limit:65536KB Total submit users: 85, Accepted users: 57 Problem 13341 : Special judge Prob…

[NC13A]反蝴蝶效应/[SPOJ-NPC2014D]General Joke 题目大意: 按顺序访问\(A_{1\sim n}(n\le10^5)\),经过\(A_i\)时身上必须有\(A_i\)的能量,每经过一个点消耗\(1\)能量,问一开始至少多少能量? 思路: \(f[i]\)表示从后往前倒推到第\(i\)个点需要多少能量,则\(f[i]=\max(A_i,f[i+1]+1)\). 源代码: #include<cstdio> #include<cctype> #inclu…

B. Spongebob and Joke time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output While Patrick was gone shopping, Spongebob decided to play a little trick on his friend. The naughty Sponge browsed th…

HDU 4969 Just a Joke pid=4969" target="_blank" style="">题目链接 推公式,r′=dr/dt=vy=v22−v12r2/R2−−−−−−−−−−−−√,可得积分公式为 ∫R0y=1/v22−v12x2/R2−−−−−−−−−−−−−√,利用三角换元去化简就可以 代码: #include <cstdio> #include <cstring> #include <cma…

  Problem A: Good Joke! Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 25  Solved: 16[Submit][Status][Web Board] Description Vadim and Roman like discussing challenging problems with each other. One day Vadim told his friend following problem: Given …

题目链接:hdu 4969 Just a Joke 题目大意:Guizeyanhua要去追一个女孩,女孩在以Guizeyanhua为圆心,半径为R的圆上匀速运动,女孩的速度为v1,Guizeyanhua的速度为v2,半径为R,Guizeyanhua腿疼仅仅能跑距离D.如今Guizeyanhua要去追女孩,前提条件是女孩,Guizeyanhua,圆心必须保持共线. 解题思路:由于有三点要共线的条件,所以Guizeyanhua和女孩的线速度必须同样,所以有v1R=vxr(vx为Guizeyanhua…

Just a Joke Description Here is just a joke, and do not take it too seriously. Guizeyanhua is the president of ACMM, and people call him President Guizeyanhua. When Guizeyanhua is walking on the road, everyone eyes on him with admiration. Recently, G…

As the old computer science joke goes: “Let’s say you have a problem, andyou decide to solve it with regular expressions. Well, now you have twoproblems.”…

B. Spongebob and Joke     While Patrick was gone shopping, Spongebob decided to play a little trick on his friend. The naughty Sponge browsed through Patrick's personal stuff and found a sequence a1, a2, ..., am of length m, consisting of integers fr…

题目:Just a Joke 传送门:http://acm.hdu.edu.cn/showproblem.php?pid=4969 分析: 呀,根本不会做,5555~(逃 http://blog.csdn.net/morejarphone/article/details/51766422 http://blog.csdn.net/u011775691/article/details/38691623 http://www.cnblogs.com/andyqsmart/p/4014534.html…

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Description While Patrick was gone shopping, Spongebob decided to play a little trick on his friend. The naughty Sponge browsed through Patrick's personal stuff and found a sequence a1, a2, ..., am of length m, consisting of integers from 1 to n, not…

数学题目 意甲冠军:的男孩向圆上的女孩跑去,保持男孩女孩圆心在同一条直线上.这过程中,男孩女孩均匀速 给出男孩女孩速度,圆的半径,男孩最长能跑的距离 问男孩是否能跑到女孩那里 能够用积分来解这道题,我们能够求出这个过程的总时间,t0.然后用t0乘以男孩的速度,再与男孩最长能跑的距离做比較 第一个公式表示的是沿着半径方向的速度 第二个公式第三个公式就是积分过程.最后得到t0(w=女孩速度除以半径) watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQvdTAxM…

Description There is a famous joke-riddle for children: Three turtles are crawling along a road. One turtle says: "There are two turtles ahead of me."  The other turtle says: "There are two turtles behind me." The third turtle says: &q…

一道水题WA那么多发,也是醉了.f看成函数的话,其实就是判断一下反函数存不存在. 坑点,只能在定义域内判断,也就是只判断b[i].没扫一遍前不能确定Impossible. #include<bits/stdc++.h> using namespace std; typedef long long ll; ; int f[maxn], b[maxn], a[maxn]; int g[maxn]; bool mul[maxn]; //#define LOCAL int main() { #ifde…

简单题. #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> using namespace std; +; int n,m; int b[maxn],f[maxn]; int cnt[maxn]; int main() { scanf("%d%d",&n,&m); memset(cnt,,sizeof cnt); ;i<=n;…

思路: 模拟,注意特判. 实现: #include <iostream> #include <cstdio> using namespace std; ], x[], y[], b[], n, m, tmp; int main() { cin >> n >> m; ; i <= n; i++) { scanf("%d", &tmp); x[tmp]++; pos[tmp] = i; } ; i <= m; i++) {…

Problem description So, the New Year holidays are over. Santa Claus and his colleagues can take a rest and have guests at last. When two "New Year and Christmas Men" meet, thear assistants cut out of cardboard the letters from the guest's name a…

w # -*- coding: utf-8 -*- import pycurl import re import cStringIO from pypinyin import lazy_pinyin import sys, locale buf = cStringIO.StringIO() GRAB_URL = 'http://www.gov.cn/test/2011-08/22/content_1930111.htm' c = pycurl.Curl() c.setopt(c.HTTPHEAD…

So, the New Year holidays are over. Santa Claus and his colleagues can take a rest and have guests at last. When two "New Year and Christmas Men" meet, thear assistants cut out of cardboard the letters from the guest's name and the host's name i…

题目链接:https://vjudge.net/problem/HDU-4969#author=0 题意:一个人在圆心以V2速度追赶一个以V1的速度进行圆周运动,问在圆心的人能否在不超过D的距离追上他,要求在追赶的过程中圆心和他们两个人三点共线. 题解:https://blog.csdn.net/weixin_30249203/article/details/96771264 1 #include<bits/stdc++.h> 2 using namespace std; 3 int main…

!= 不等于 select empno,ename,job from scott.emp where job!='manager' ^= 不等于 select empno,ename,job from scott.emp where job^='manager' <>不等于 select empno,ename,job from scott.emp where job<>'manager' <小于 select sal from scott.emp where sal<…

前言: 最近飞机失联的太多,明天要飞北京处理服务器双机热备的问题,航空保险已买,单号是:TF10122913. 至于我的银行卡密码,在我枕头下面的字条里,要是我之后没再更新文章,请通知我家人,哈哈哈哈. 好了,Joke 被 Play 后,下面 Enter 正文. 背景: 话说:使用CYQ.Data时,会经常断点MDataTable的对象,为了查看表格的数据内容,在监视里会常ToDataTable(),然后借可DataTable的可视化方式查看表格. 近日:心中莫名就来了一句话,不转行不行?狠想直…

Oracle中算术操作符(+)(-)(*)(/) 值得注意的是:/ 在oracle中就相当于显示中的除法 5/2 = 2.5 比较操作符: 其中等号可以换成其他运算符:(后面为该操作符的单条件查询样例) != 不等于 select empno,ename,job from scott.emp where job!='manager'    ^= 不等于 select empno,ename,job from scott.emp where job^='manager'    <>不等于  se…