题目链接:https://vjudge.net/problem/POJ-2289 Jamie's Contact Groups Time Limit: 7000MS   Memory Limit: 65536K Total Submissions: 8147   Accepted: 2736 Description Jamie is a very popular girl and has quite a lot of friends, so she always keeps a very lon…

Jamie's Contact Groups Time Limit: 7000MS   Memory Limit: 65536K Total Submissions: 6511   Accepted: 2087 Description Jamie is a very popular girl and has quite a lot of friends, so she always keeps a very long contact list in her cell phone. The con…

Jamie's Contact Groups Time Limit:7000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 2289 Description Jamie is a very popular girl and has quite a lot of friends, so she always keeps a very long contact list…

题意: Jamie有很多联系人,但是很不方便管理,他想把这些联系人分成组,已知这些联系人可以被分到哪个组中去,而且要求每个组的联系人上限最小,即有一整数k,使每个组的联系人数都不大于k,问这个k最小是多少? 题目分析: 多重匹配,二分枚举所有极限值. 多重匹配如何匹配? 假如我们有两个集合X, Y 但是呢 Y可以匹配多个X, 这个时候我们需要给这个匹配设置一个极限值.比如Y可以匹配三个X. 假如匹配的值不到三个X我们就将他们匹配, 直到到达极限值为止.在这里Y要保存所有的与之匹配的X,若是匹配值…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1669 题目大意: 给你各个人可以属于的组,把这些人分组,使这些组中人数最多的组人数最少,并输出这个人数.解题思路: 一组可以有多人,一人只能分到一组,显然是多重匹配,只要枚举一下每组的限制人数limit,用多重匹配判断即可. 代码 #include<iostream> #include<cstdio> #include<cstring> #include<algori…

Jamie's Contact Groups Time Limit: 7000MS   Memory Limit: 65536K Total Submissions: 7721   Accepted: 2599 Description Jamie is a very popular girl and has quite a lot of friends, so she always keeps a very long contact list in her cell phone. The con…

题目链接 题意:Jamie有很多联系人,但是很不方便管理,他想把这些联系人分成组,已知这些联系人可以被分到哪个组中去,而且要求每个组的联系人上限最小,即有一整数k,使每个组的联系人数都不大于k,问这个k最小是多 少?   一对多的二分图的多重匹配.二分图的多重匹配算法的实现类似于匈牙利算法,对于集合x中的元素xi,找到一个与其相连的元素yi后,检查匈牙利算法的两个条件是否成立,若yi未被匹配,则将 xi,yi匹配.否则,如果与yi匹配的元素已经达到上限,那么在所有与yi匹配的元素中选择一个元素,…

思路: 二分+最大流.实现: #include <stdio.h> #include <stdlib.h> #include <limits.h> #include <string.h> #include <assert.h> #include <queue> #include <vector> #include <algorithm> #include <iostream> #include &l…

注意POJ数组越界可能返回TLE!!! 网络流的maxn大小要注意 其他没什么了 裸二分答案+isap乱搞 不过复杂度没搞懂 V=1e3 E = 1e5 那ISAP的O(V^2E)怎么算都不行啊 /*--------------------------------------------------------------------------------------*/ #include <algorithm> #include <iostream> #include <…

Jamie's Contact Groups Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 125536/65536 K (Java/Others) 题目链接:http://poj.org/problem?id=2289 Description: Jamie is a very popular girl and has quite a lot of friends, so she always keeps a very long…