Java for LeetCode 162 Find Peak Element】的更多相关文章

A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fi…
A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fi…
A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fi…
A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fi…
A peak element is an element that is greater than its neighbors. Given an input array nums, where nums[i] ≠ nums[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the pea…
Problem: A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the pe…
A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fi…
题目: A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks i…
一.题目链接: https://leetcode.com/problems/find-peak-element/ 二.题目大意: 给定一个长度为N的一维数组,数组是无序的,要求找到数组中的极大值(或局部最大值),并返回该极大值的下标,并假设 nums[-1] = nums[n] = -∞.:当某元素同时大于它两边的元素时,则该元素是数组中的一个极大值,数组中若存在多个极大值,则返回任意一个即可. 算法的时间复杂度要求为log级别. 三.题解: 这个问题的最直观的解法,就是遍历一遍数组,然后判断每…
[LeetCode]162. Find Peak Element 解题报告(Python) 标签(空格分隔): LeetCode 题目地址:https://leetcode.com/problems/find-peak-element/description/ 题目描述: A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], fi…
A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fi…
Find Peak Element A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. You may imagine that num[-1] = num[n] = -∞. For example, in array [1, 2, 3, 1],…
Find Peak Element A peak element is an element that is greater than its neighbors. Given an input array nums, where nums[i] ≠ nums[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to…
Find Peak Element A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one…
A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fi…
A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fi…
A peak element is an element that is greater than its neighbors. Given an input array nums, where nums[i] ≠ nums[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the pea…
A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fi…
  A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is…
题目: A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks i…
根据题目可知,输入为:一个相邻元素不相等的数列,输出为:其中一个(上)峰值的序号.并且要求时间复杂度为logn 分析:由于题目要求时间复杂度为logn,因此不能进行全部遍历.又因为只需要找到其中的一个峰值,那么,每次对半分,便可以达到logn的复杂度. 根据对半分的思路继续想,不难发现只要确定了中间位置的数是处在上升阶段还是下降阶段,就可以确定在某一侧必有一个峰值. 往复多次,即可找出两个点,其中一个一定处于某一个峰值上. java代码: public int findPeakElement(i…
Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element. For example, Given [3,2,1,5,6,4] and k = 2, return 5. 解题思路: 本题是<算法导论>原题,9.2节用归并的思路给出了时间复杂度为O(n)的算法,9.3节给出了最…
峰值元素是指其值大于左右相邻值的元素.给定一个输入数组,其中 num[i] ≠ num[i+1],找到峰值元素并返回其索引.数组可能包含多个峰值,在这种情况下,返回到任何一个峰值所在位置都可以.你可以想象得到  num[-1] = num[n] = -∞.例如,在数组 [1, 2, 3, 1]中 3 是峰值元素您的函数应该返回索引号2.注意:你的解决方案应该是对数复杂度的. 详见:https://leetcode.com/problems/find-peak-element/descriptio…
解题思路: 直接修改中序遍历函数即可,JAVA实现如下: int res = 0; int k = 0; public int kthSmallest(TreeNode root, int k) { this.k = k; inorderTraversal(root); return res; } public List<Integer> inorderTraversal(TreeNode root) { List<Integer> list = new ArrayList<…
162. 寻找峰值 峰值元素是指其值大于左右相邻值的元素. 给定一个输入数组 nums,其中 nums[i] ≠ nums[i+1],找到峰值元素并返回其索引. 数组可能包含多个峰值,在这种情况下,返回任何一个峰值所在位置即可. 你可以假设 nums[-1] = nums[n] = -∞. 示例 1: 输入: nums = [1,2,3,1] 输出: 2 解释: 3 是峰值元素,你的函数应该返回其索引 2. 示例 2: 输入: nums = [1,2,1,3,5,6,4] 输出: 1 或 5 解…
162. 寻找峰值 162. Find Peak Element 题目描述 峰值元素是指其值大于左右相邻值的元素. 给定一个输入数组 nums,其中 nums[i] ≠ nums[i+1],找到峰值元素并返回其索引. 数组可能包含多个峰值,在这种情况下,返回任何一个峰值所在位置即可. 你可以假设 nums[-1] = nums[n] = -∞. 每日一算法2019/6/1Day 29LeetCode162. Find Peak Element 示例 1: 输入: nums = [1,2,3,1]…
二分法相关 153. Find Minimum in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. (M…
Leetcode之二分法专题-162. 寻找峰值(Find Peak Element) 峰值元素是指其值大于左右相邻值的元素. 给定一个输入数组 nums,其中 nums[i] ≠ nums[i+1],找到峰值元素并返回其索引. 数组可能包含多个峰值,在这种情况下,返回任何一个峰值所在位置即可. 你可以假设 nums[-1] = nums[n] = -∞. 示例 1: 输入: nums = [1,2,3,1] 输出: 2 解释: 3 是峰值元素,你的函数应该返回其索引 2. 示例 2: 输入:…
题目 A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is…
A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fi…