下面是difficulty 1的题 1003   Max Sum 最长递增子序列.非常经典,最棒的解法是在线算法O(n)的复杂度. 贴的呢,是用dp做的代码. 先是一个高亮的dp递推式,然后找到最大处,用k记录.即所求的子序列的结尾,之后倒推,用减法推出子序列的开头位置. 要注意的点就是各个变量的初始化,初始化不好,很容易WA.还有找子序列的头的时候,倒推的时候找到等值的数是不跳出的,但是更新gx的值,因为0的存在. #include <iostream> #include <cstri…
传送门 Description Dynamic Programming, short for DP, is the favorite of iSea. It is a method for solving complex problems by breaking them down into simpler sub-problems. It is applicable to problems exhibiting the properties of overlapping sub-problem…
Dynamic Programming? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Problem Description Dynamic Programming, short for DP, is the favorite of iSea. It is a method for solving complex problems by breaking them down…
//连续的和的绝对值最小 # include <stdio.h> # include <string.h> # include <algorithm> # include <math.h> using namespace std; int main() { int t,i,j,num,n,min1; int sum[1010],a[1010]; int cas=0; while(~scanf("%d",&t)) { while(t…
pid=4972" target="_blank" style="">题目链接:hdu 4972 A simple dynamic programming problem 题目大意:两支球队进行篮球比赛,每进一次球后更新比分牌,比分牌的计数方法是记录两队比分差的绝对值,每次进球的分可能是1,2,3分. 给定比赛中的计分情况.问说最后比分有多少种情况. 解题思路:分类讨论: 相邻计分为1-2或者2-1的时候,会相应有两种的的分情况 相邻计分之差大于3或…
http://acm.hdu.edu.cn/showproblem.php?pid=4972 ++和+1还是有区别的,不可大意. A simple dynamic programming problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 307    Accepted Submission(s): 117 Problem D…
文章以 CC-BY-SA 方式共享,此说明高于本站内其他说明. 本文尚未完工,但内容足够丰富,故提前发布. 内容包含大量 \(\LaTeX\) 公式,渲染可能需要一些时间,请耐心等待渲染(约 5s). 0x00 前言 题单将介绍介绍动态规划(Dynamic Programming, DP)及其解决的问题.根据其设计的算法及优化. 动态规划是一种通过把原问题分解为相对简单的子问题的方式求解复杂问题的方法. 由于动态规划并不是某种具体的算法,而是一种解决特定问题的方法,因此它会出现在各式各样的数据结…
March 26, 2013 作者:Hawstein 出处:http://hawstein.com/posts/dp-novice-to-advanced.html 声明:本文采用以下协议进行授权: 自由转载-非商用-非衍生-保持署名|Creative Commons BY-NC-ND 3.0 ,转载请注明作者及出处. 前言 本文翻译自TopCoder上的一篇文章: Dynamic Programming: From novice to advanced ,并非严格逐字逐句翻译,其中加入了自己的…
We began our study of algorithmic techniques with greedy algorithms, which in some sense form the most natural approach to algorithm design. Faced with a new computational problem, we've seen that it's not hard to propose multiple possible greedy alg…
转载自:http://blog.csdn.net/speedme/article/details/24231197 1. 什么是动态规划 ------------------------------------------- dynamic programming is a method for solving complex problems by breaking them down into simpler subproblems. (通过把原问题分解为相对简单的子问题的方式求解复杂问题的…