Leetcode-Convert Sorted Array to BST】的更多相关文章

LeetCode:Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST 分析:找到数组的中间数据作为根节点,小于中间数据的数组来构造作为左子树,大于中间数据的数组来构造右子树,递归解法如下 /** * Definition for binary tree * struct…
Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST.SOLUTION 1:使用递归解决. base case: 当索引值超过时,返回null. 递归主体:构造根节点,调用递归构造左右子树.并将左右子树挂在根节点上. 返回值:返回构造的根节点. GITHUB: https:…
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 这道题是要将有序数组转为二叉搜索树,所谓二叉搜索树,是一种始终满足左<根<右的特性,如果将二叉搜索树按中序遍历的话,得到的就是一个有序数组了.那么反过来,我们可以得知,根节点应该是有序数组的中间点,从中间点分开为左右两个有序数组,在分别找出其中间点作为原中间点的左右两个子节点,这不就是是二分查找法的核…
题目: Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 思路: 总是取中间点为root package bst; public class ConvertSortedArrayToBinarySearchTree { public TreeNode sortedArrayToBST(int[] nums) { return constructBST(…
1.Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 2.Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 这里两道题目.是连在一起的两题.给你一个排好序(升序)的数组或者链表,将它们…
Description: Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 给一个升序有序的数组,构建一个平衡的二叉查找树. 要平衡就要找中间的数来做头结点,递归构造. /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode lef…
题意: 将一个有序的数组建成一棵平衡的BST树. 思路: 因为数组已经有序,每次可以从中点开始建根,再递归下去分别处理左/右子树. /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Soluti…
原题地址:http://oj.leetcode.com/problems/convert-sorted-array-to-binary-search-tree/ 题意:将一个排序好的数组转换为一颗二叉查找树,这颗二叉查找树要求是平衡的. 解题思路:由于要求二叉查找树是平衡的.所以我们可以选在数组的中间那个数当树根root,然后这个数左边的数组为左子树,右边的数组为右子树,分别递归产生左右子树就可以了. 代码: # Definition for a binary tree node # class…
排好序的... 中间是root , root左边是left,root右边是right 递归建树. /** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: TreeNode* cr…
108. Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the tw…