Red and Black Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 13508 Accepted Submission(s): 8375 Problem Description There is a rectangular room, covered with square tiles. Each tile is colored ei…
Problem Description There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on red tiles, he can mo…
Problem Description There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on red tiles, he can mo…
Red and Black Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 7337 Accepted Submission(s): 4591 Problem Description There is a rectangular room, covered with square tiles. Each tile is color…
Problem Description Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color…
Problem Description The digital root of a positive integer is found by summing the digits of the integer. If the resulting value is a single digit then that digit is the digital root. If the resulting value contains two or more digits, those digits a…
HDOJ 1312 Red and Black http://acm.hdu.edu.cn/showproblem.php?pid=1312 很裸的dfs,在dfs里面写上ans++,能到几个点就调了几次dfs,最后ans就是答案 #include<cstdio> #include<iostream> using namespace std; ][]; int n,m,si,sj,ans; ][] = {{,}, {-,}, {,-}, {,}}; int dfs(int x, i…
