HDU 5015 233 Matrix

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HDU - 5015 233 Matrix（杨辉三角/前缀+矩阵快速幂）

233 Matrix In our daily life we often use 233 to express our feelings. Actually, we may say 2333, 23333, or 233333 ... in the same meaning. And here is the question: Suppose we have a matrix called 233 matrix. In the first line, it would be 233, 2333…

HDU 5015 233 Matrix（网络赛1009）矩阵快速幂

先贴四份矩阵快速幂的模板:http://www.cnblogs.com/shangyu/p/3620803.html http://www.cppblog.com/acronix/archive/2010/08/23/124470.aspx?opt=admin http://www.cnblogs.com/vongang/archive/2012/04/01/2429015.html http://www.cnblogs.com/yan-boy/archive/2012/11/29/279529…

hdu 5015 233 Matrix （矩阵高速幂）

233 Matrix Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 749 Accepted Submission(s): 453 Problem Description In our daily life we often use 233 to express our feelings. Actually, we may s…

HDU - 5015 233 Matrix (矩阵快速幂）

In our daily life we often use 233 to express our feelings. Actually, we may say 2333, 23333, or 233333 ... in the same meaning. And here is the question: Suppose we have a matrix called 233 matrix. In the first line, it would be 233, 2333, 23333...…

hdu 5015 233 Matrix(构造矩阵)

http://acm.hdu.edu.cn/showproblem.php?pid=5015 由于是个二维的递推式,当时没有想到能够这样构造矩阵.从列上看,当前这一列都是由前一列递推得到.依据这一点来构造矩阵.令b[i]代表第i列,是一个(n+2)*1的矩阵,即b[1] = [1,233......],之所以在加了两行,是要从前一个矩阵b[i-1]得到b[i]中的第二个数2333...,再构造一个转换矩阵a,它是一个(n+2)*(n+2)的矩阵,那么a^(m-1) * b就是第m列. /* a矩…

HDU 5015 233 Matrix --矩阵快速幂

题意:给出矩阵的第0行(233,2333,23333,...)和第0列a1,a2,...an(n<=10,m<=10^9),给出式子: A[i][j] = A[i-1][j] + A[i][j-1],要求A[n][m]. 解法:看到n<=10和m<=10^9 应该对矩阵有些想法,现在我们假设要求A[a][b],则A[a][b] = A[a][b-1] + A[a-1][b] = A[a][b-1] + A[a-1][b-1] + A[a-2][b] = ... 这样相当于右图:,红…

题意:给定一个矩阵的第0列的第1到n个数,第一行第1个数开始每个数分别为233, 2333........,求第n行的第m个数. 分析: 其实也没那么难,自己想了半天还没往对的方向想,m最大1e9,应该立即想到要用到快速幂,关键在于递推矩阵. 递推矩阵的作用是依次算出每一列,第1列第一个数233是前一列的23*10+3,将前一列增加一个元素[3, 23, a1, a2,....an],然后第一列第一个数为3,对应向量[1, 0, 0, 0.....0],233对应向量[1, 10, 0, ...…