二分图:https://blog.csdn.net/c20180630/article/details/70175814 https://blog.csdn.net/flynn_curry/article/details/52966283 匈牙利算法模板:https://blog.csdn.net/sunny_hun/article/details/80627351 例题:hdu 1150 Machine Schedule 参考:https://www.cnblogs.com/qq-star/p…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1150 Machine Schedule Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6733    Accepted Submission(s): 3375 Problem Description As we all know, mach…

pid=1150">Machine Schedule Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 5424    Accepted Submission(s): 2691 Problem Description As we all know, machine scheduling is a very classical pro…

Machine Schedule Time Limit: 1 Sec  Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1150 Description As we all know, machine scheduling is a very classical problem in computer science and has been studied for a very long history.…

Machine Schedule Time Limit: 1 Sec  Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1150 Description As we all know, machine scheduling is a very classical problem in computer science and has been studied for a very long history.…

//两道大水……哦不 两道结论题 结论:二部图的最小覆盖数=二部图的最大匹配数 有向图的最小覆盖数=节点数-二部图的最大匹配数 //hdu 1150 #include<cstdio> #include<iostream> #include<cmath> #include<algorithm> #include<cstring> #include<cstdlib> #include<queue> #include<ve…

Machine Schedule Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5316    Accepted Submission(s): 2631 Problem Description As we all know, machine scheduling is a very classical problem in comput…

Machine Schedule Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 9461    Accepted Submission(s): 4755 Problem Description As we all know, machine scheduling is a very classical problem in compu…

二分图匹配(匈牙利算法) 1.一个二分图中的最大匹配数等于这个图中的最小点覆盖数 König定理是一个二分图中很重要的定理,它的意思是,一个二分图中的最大匹配数等于这个图中的最小点覆盖数.如果你还不知道什么是最小点覆盖,我也在这里说一下:假如选了一个点就相当于覆盖了以它为端点的所有边,你需要选择最少的点来覆盖所有的边. 2.最小路径覆盖=最小路径覆盖＝|G|-最大匹配数 在一个N*N的有向图中,路径覆盖就是在图中找一些路经,使之覆盖了图中的所有顶点, 且任何一个顶点有且只有一条路径与之关联:(如…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1150 有两个机器a和b,分别有n个模式和m个模式.下面有k个任务,每个任务需要a的一个模式或者b的一个模式完成. 两个机器初始都是0模式,一个机器转换一个模式需要重启一次.问你最少需要重启几次能完成所有的任务. 不太明显的二分匹配,将每个任务的两个模式连线,大概就能看出来这是个最小点覆盖问题. /* 将下面任务的a状态和b状态连边,线的个数就是任务个数. 要使重启次数最少,那么就要使选择的点最少而且…