用什么语言解法都差不多,思路都是一样,递归,这其中只要注重于开始和结果的状态就可以了,对于中间过程,并不需要深究.(我细细思考了一下,还是算了.=_=) 代码其实很简单注重的是思路. 问题描述:有一个梵塔,塔内有三个座A.B.C,A座上有诺干个盘子,盘子大小不等,大的在下,小的在上.把这些个盘子从A座移到C座,中间可以借用B座但每次只能允许移动一个盘子,并且在移动过程中,3个座上的盘子始终保持大盘在下,小盘在上. 简要概括一下,每次只能移动一个盘子,小盘子不能被大盘子压着,源座是A.目标座是C,…

Hanoi Tower Troubles Again! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 602    Accepted Submission(s): 418 Problem Description People stopped moving discs from peg to peg after they know the…

链接:ZOJ1239 Hanoi Tower Troubles Again! Description People stopped moving discs from peg to peg after they know the number of steps needed to complete the entire task. But on the other hand, they didn't not stopped thinking about similar puzzles with…

#include<stdio.h>int main(){ int m; void hanoi(int n,char x,char y,char z); printf("input the number of disk:\n"); scanf("%d",&m); hanoi(m,'A','B','C'); return 0;}void hanoi(int n,char x,char y,char z){ void move(char a,char…

Description You all must know the puzzle named "The Towers of Hanoi". The puzzle has three pegs and N discs of different radii, initially all disks are located on the first peg, ordered by their radii - the largest at the bottom, the smallest at…

2016-03-19 17:01:35 问题描述: 假设有三个命名为 A B C 的塔座 ,在塔座A上插有n个直径大小不相同,由小到大编号为1 ,2 ,3 ,··· ,n的圆盘,要求将A座上的圆盘移至塔座C 并按同样的顺序叠排,圆盘移动必须遵守下列规则: 1:每次只能移动一个圆盘 2:圆盘可以插在任意一个塔座上 3:任何时刻都不能将一个较大的圆盘放在一个较小的圆盘上 f(n):原始A柱有n个圆盘,全部移动到C柱的移动次数 我们要将编号为n的圆盘移动到C柱上,首先须得将A柱上的n-1个圆盘从A->…

3.4 In the classic problem of the Towers of Hanoi, you have 3 towers and N disks of different sizes which can slide onto any tower. The puzzle starts with disks sorted in ascending order of size from top to bottom (i.e., each disk sits on top of an e…

/* 课本p54页*/ #include<stdio.h> #include <iostream> using namespace std; void move(int n, char a, char b){ printf("Move %c to %c.\n",a,b); } void hanoi(int n, char a, char b, char c){//把n个盘子从a柱子移动到b柱子 ) { hanoi(n - , a, c, b);// 把n-1个盘…

#include<stdio.h> void hanoi(int n,char x,char y,char z) { ; ) printf("%d. Move disk %d form %c to %c\n", ++c,n,x,z); else { hanoi(n-,x,z,y); printf("%d. Move disk %d form %c to %c\n", ++c,n,x,z); hanoi(n-,y,x,z); } } void main()…

  算法训练 Hanoi问题   时间限制:1.0s   内存限制:512.0MB      问题描述 如果将课本上的Hanoi塔问题稍做修改:仍然是给定N只盘子,3根柱子,但是允许每次最多移动相邻的M只盘子(当然移动盘子的数目也可以小于M),最少需要多少次? 例如N=5,M=2时,可以分别将最小的2个盘子.中间的2个盘子以及最大的一个盘子分别看作一个整体,这样可以转变为N=3,M=1的情况,共需要移动7次. 输入格式 输入数据仅有一行,包括两个数N和M(0<=M<=N<=8) 输出格式…