一种矩形切割的做法: 1 #include<bits/stdc++.h> 2 using namespace std; 3 typedef long long LL; 4 const int maxn=1005; 5 struct node{//矩形的结构体 6 LL x1,y1,x2,y2; 7 }a[maxn]; 8 int n,cnt=0; 9 10 void Cut(LL id,LL x1,LL y1,LL x2,LL y2){//矩形切割 11 LL k1,k2,k3,k4; 12…
P3045 [USACO12FEB]牛券Cow Coupons 71通过 248提交 题目提供者洛谷OnlineJudge 标签USACO2012云端 难度提高+/省选- 时空限制1s / 128MB 提交  讨论  题解 最新讨论更多讨论 86分求救 题目描述 Farmer John needs new cows! There are N cows for sale (1 <= N <= 50,000), and FJ has to spend no more than his budget…
题目描述 Being a secret computer geek, Farmer John labels all of his cows with binary numbers. However, he is a bit superstitious, and only labels cows with binary numbers that have exactly K "1" bits (1 <= K <= 10). The leading bit of each la…
P3048 [USACO12FEB]牛的IDCow IDs 12通过 67提交 题目提供者lin_toto 标签USACO2012 难度普及/提高- 时空限制1s / 128MB 提交  讨论  题解 最新讨论更多讨论 谁能解释一下这个样例啊.... 题目描述 Being a secret computer geek, Farmer John labels all of his cows with binary numbers. However, he is a bit superstitiou…
题目链接 嗯,毒瘤题. 首先有一个结论,就是最小矩形一定有条边和凸包重合.脑补一下就好了. 然后枚举凸包的边,用旋转卡壳维护上顶点.左端点.右端点就好了. 上顶点用叉积,叉积越大三角形面积越大,对应的高也就越大.两边的点用点积,点积越大投影越大. 然后就是精度问题.这种实数计算最好不要直接用比较运算符,要用差和\(eps\)的关系来比较,我就是一直卡在这里.还好有爆炸\(OJ\)离线题库提供的数据... #include <cstdio> #include <cmath> #inc…
P3047 [USACO12FEB]附近的牛Nearby Cows 题目描述 Farmer John has noticed that his cows often move between nearby fields. Taking this into account, he wants to plant enough grass in each of his fields not only for the cows situated initially in that field, but…
P3047 [USACO12FEB]附近的牛Nearby Cows 题目描述 Farmer John has noticed that his cows often move between nearby fields. Taking this into account, he wants to plant enough grass in each of his fields not only for the cows situated initially in that field, but…
18.09.09模拟赛T1. 一道数学题. 题目传送门 首先把对角线当成是某个点的移动轨迹,从左下到右上. 那么这个点每上升一个单位长度,就穿过一个格子. 每右移一个单位长度,也会穿过一个格子. 例外:穿过格点,会减少穿过的格子数. 初步的结论:R*C的矩形,对角线穿过的格子数N=R+C-gcd(R,C). 那么我们只需算出这个方程的解的个数. 可以看出,R.C和gcd(R,C)都是gcd(R,C)的倍数. 那么N显然也是. 设N/gcd(R,C)=n,R/gcd(R,C)=r,C/gcd(R,…
题目链接: 洛谷 P3187 [HNOI2007]最小矩形覆盖 BZOJ 1185: [HNOI2007]最小矩形覆盖 Description 给定一些点的坐标,要求求能够覆盖所有点的最小面积的矩形, 输出所求矩形的面积和四个顶点坐标 Input 第一行为一个整数n(3<=n<=50000) 从第2至第n+1行每行有两个浮点数,表示一个顶点的x和y坐标,不用科学计数法 Output 第一行为一个浮点数,表示所求矩形的面积(精确到小数点后5位), 接下来4行每行表示一个顶点坐标,要求第一行为y坐…
洛谷P2241-统计方形 题目描述: 有一个 \(n \times m\) 方格的棋盘,求其方格包含多少正方形.长方形(不包含正方形). 思路: 所有方形的个数=正方形的个数+长方形的个数.对于任意一个\(x\times y\)的矩形,以这个方形右下角的那个块作为要在矩形内选择正方形\长方形的右下角,则正方形的个数为\(min(x,y)\),长方形的个数为\(x*y\). 解释如下:对于一个\(x\times y\)的矩形,右下角的块必选,则能和这个块组成的正方形的右上角块全在这个主对角线上,而…