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Billboard 通过这题,我知道了要活用线段树的思想,而不是拘泥于形式, 就比如这题 显然更新和查询放在一起很简单 但如果分开写 那么我觉得难度会大大增加 [题目链接]Billboard [题目类型]区间求最大值的位置update的操作在query里做了 &题意: h*w的木板,放进一些1*L的物品,求每次放空间能容纳且最上边的位子 &题解: 思路:每次找到最大值的位子,然后减去L 线段树功能:query 区间求最大值的位置(直接把update的操作在query里做了) [时间复杂度]…
三维场景中对于渲染效果不是很精致的物体可以使用BillBoard技术实现,使用该技术需要将物体实时朝向摄像机,即计算billboard的旋转矩阵M. 首先根据摄像机位置cameraPos和billBoard中心点的坐标centerPos,计算出向量look = centerPos - cameraPos; 然后计算bilboard的向量right = look * cameraUP; 最后计算billboard的向量up = right * look; 最终得到M = mat(right,up,…
题目链接: 传送门 Billboard Time Limit: 2000MS     Memory Limit: 32768 K Description At the entrance to the university, there is a huge rectangular billboard of size hw (h is its height and w is its width). The board is the place where all possible announcem…
 Billboard Time Limit:8000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Description 在学校的入口处有一个巨大的矩形广告牌,高为h,宽为w.所有种类的广告都可以贴,比如ACM的广告啊,还有餐厅新出了哪些好吃的,等等..   在9月1号这天,广告牌是空的,之后广告会被一条一条的依次贴上去.   每张广告都是高度为1宽度为wi的细长的矩形纸条.   贴广告的人总是会优先选择最上面的位置来…
Problem Description At the entrance to the university, there is a huge rectangular billboard of size h*w (h is its height and w is its width). The board is the place where all possible announcements are posted: nearest programming competitions, chang…
Billboard Time Limit:8000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Description At the entrance to the university, there is a huge rectangular billboard of size h*w (h is its height and w is its width). The board is t…
Billboard Time Limit: 20000/8000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 19225    Accepted Submission(s): 8042 Problem Description At the entrance to the university, there is a huge rectangular billboard of…
Billboard Time Limit: 20000/8000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 10594    Accepted Submission(s): 4686 Problem Description At the entrance to the university, there is a huge rectangular billboard of s…
Strange Billboard 题目链接: http://acm.hust.edu.cn/vjudge/contest/129733#problem/A Description The marketing and public-relations department of the Czech Technical University has designed a new reconfigurable mechanical Flip-Flop Bill-Board (FFBB). The b…
题目链接 题意 : 给你一个矩阵,有黑有白,翻转一个块可以让上下左右都翻转过来,问最少翻转多少次能让矩阵变为全白. 思路 : 我们从第一行开始枚举要翻转的状态,最多可以枚举到2的16次方,因为你只要第一行的确定了,第二行要翻转的也就确定了,所以第一行的状态决定了最后的状态.看了网上大神,真是让位运算废了啊,,,,,太复杂了...... #include <iostream> #include <stdio.h> #include <string.h> #include…