【Lintcode】137.Clone Graph】的更多相关文章

题目: Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors. How we serialize an undirected graph: Nodes are labeled uniquely. We use # as a separator for each node, and , as a separator for node label and each…
Clone Graph Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors. OJ's undirected graph serialization: Nodes are labeled uniquely. We use # as a separator for each node, and , as a separator for node label an…
题目如下: Given the head of a graph, return a deep copy (clone) of the graph. Each node in the graph contains a label (int) and a list (List[UndirectedGraphNode]) of its neighbors. There is an edge between the given node and each of the nodes in its neig…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 DFS BFS 日期 题目地址:https://leetcode.com/problems/clone-graph/ 题目描述 Given a reference of a node in a connected undirected graph, return a deep copy (clone) of the graph. Each node…
[LeetCode]785. Is Graph Bipartite? 解题报告(Python) 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/is-graph-bipartite/description/ 题目描述: Given an undirected graph, return true if and only if it is bipartite. Re…
[LeetCode]137. Single Number II 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/single-number-ii/description/ 题目描述: Given an array of integers, every element appears three times except for one, which appears exactly once. Find that singl…
[参考资料] https://stackoverflow.com/questions/8329485/unable-to-find-remote-helper-for-https-during-git-clone 问题现象: git clone https://xxxxx 报错:git fatal: Unable to find remote helper for 'https' 一般都是因为缺少了 curl-devel. 所以,可以先安装 curl-devel,然后重新编译安装git $ yu…
 二分法:通过O(1)的时间,把规模为n的问题变为n/2.T(n) = T(n/2) + O(1) = O(logn). 基本操作:把长度为n的数组,分成前区间和后区间.设置start和end下标.int start = 0, end = nums.length - 1.循环结束条件为start + 1 < end ,即相邻时结束循环,所以最后需判断start和end中哪个是目标值.指针变化为start = mid,取后半区间:end = mid,取前半区间. 经典二分搜索:1. First p…
论文阅读笔记(十七)ICCV2017的扩刊(会议论文[传送门]) 改进部分: (1)惩罚函数:原本由两部分组成的惩罚函数,改为只包含 Sequence Cost 函数: (2)对重新权重改进: ① Positive Re-Weighting: 其中 若太大,则选择的样本标签的可信度小:若太小,则样本数量不足以进行矩阵学习,因此设置如下的: 其中,σ为 [0, 1],如果 σ = 1,则说明充分相信样本估计的可信度,反之设置为 σ = 0. ② Negative Re-Weighting: 对于所…
网络流/二分图最小点权覆盖 果然还是应该先看下胡伯涛的论文…… orz proverbs 题意: N个点M条边的有向图,给出如下两种操作.删除点i的所有出边,代价是Ai.删除点j的所有入边,代价是Bj.求最后删除图中所有的边的最小代价. 其实就是二分图最小点权覆盖. 定义:从x或者y集合中选取一些点,使这些点覆盖所有的边,并且选出来的点的权值尽可能小. 题解: 拆点.n个点拆成2n个点(左右各n个,i与(i+n)对应,之间连容量INF的边),S和i连容量为Ai的边,(i+n)与T之间连容量为Bi…