using prev class Solution { List<List<Integer>> res = new ArrayList<List<Integer>>(); public List<List<Integer>> subsets(int[] nums) { List<Integer> temp = new ArrayList<>(); back(temp,nums, 0); return res;…
Yet Another Source Code for LintCode Current Status : 232AC / 289ALL in Language C++, Up to date (2016-02-10) For more problems and solutions, you can see my LintCode repository. I'll keep updating for full summary and better solutions. See cnblogs t…
for the backtracking part, thanks to the video of stanford cs106b lecture 10 by Julie Zelenski for the nice explanation of recursion and backtracking, highly recommended. in hdu 2553 cout N-Queens solutions problem, dfs is used. // please ignore, bel…
Given a collection of integers that might contain duplicates, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. Example: Input: [1,2,2] Output: [ [2], [1], [1,2,2], [2,2], [1,2], [] ] 这个题目思路…
根据issac3 用Java总结了backtracking template, 我用他的方法改成了Python. 以下为template. def backtrack(ans, temp, nums, start): # 可能有start, 也可能没有 if len(temp) == len(nums): ans.append(temp) else: for i in range(start, len(nums)): if nums[i] not in temp: backtrack(ans,…
Given a set of distinct integers, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. Example: Input: nums = [1,2,3] Output: [ [3], [1], [2], [1,2,3], [1,3], [2,3], [1,2], [] ] …
