$n \leq 50000$个人,每个人有$K \leq 10$个属性,现对每一个前缀问:进行比赛,每次任意两人比任意属性,小的淘汰(保证同一属性不会出现两个相同的数),最终有几个人有可能获胜. 明显是一个竞赛图了,缩完点就是求拓扑序最高那个强连通分量的大小.现在要一个一个把人加入. 可以观察到,缩完点之后,两个分量之间一定有边,表示一个分量“完胜”另一个,就是不管比哪个属性这个分量里的人都能赢另外一个.所以把分量按某个属性的最小值排序的话,任意一个属性与此同时都是按最小值排序的,同时也是按任意…

A. Tennis Tournament time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output A tennis tournament with n participants is running. The participants are playing by an olympic system, so the winners mo…

Rock-Paper-Scissors TournamentTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2178 Accepted Submission(s): 693 Problem DescriptionRock-Paper-Scissors is game for two players, A and B, who each choo…

CF 628A 题目大意:给定n,b,p,其中n为进行比赛的人数,b为每场进行比赛的每一位运动员需要的水的数量, p为整个赛程提供给每位运动员的毛巾数量, 每次在剩余的n人数中,挑选2^k=m(m <=n)个人进行比赛,剩余的n-m个人直接晋级, 直至只剩一人为止,问总共需要的水的数量和毛巾的数量 解题思路:毛巾数很简单: n*p即可 水的数量:1,2,4,8,16,32,64,128,256,512,提前打成一个表, 根据当前剩余的人数n在表中二分查找最大的小于等于n的数,结果即为本次进行比赛…

1218. Episode N-th: The Jedi Tournament Time limit: 1.0 secondMemory limit: 64 MB Decided several Jedi Knights to organize a tournament once. To know, accumulates who the largest amount of Force. Brought each Jedi his lightsaber with him to the tourn…

Episode N-th: The Jedi Tournament Time limit: 1.0 secondMemory limit: 64 MB Decided several Jedi Knights to organize a tournament once. To know, accumulates who the largest amount of Force. Brought each Jedi his lightsaber with him to the tournament.…

题目链接: 题目 E. Another Sith Tournament time limit per test2.5 seconds memory limit per test256 megabytes inputstandard input outputstandard output 问题描述 The rules of Sith Tournament are well known to everyone. n Sith take part in the Tournament. The Tour…

 Knight Tournament time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output Hooray! Berl II, the king of Berland is making a knight tournament. The king has already sent the message to all knights…

假设个体(individual)用\(h_i\)表示,该个体的适应度(fitness)为\(Fitness(h_i)\),被选择的概率为\(P(h_i)\). 另外假设种群(population)的个体总数为\(N\). I. Fitness Selection 该方法也叫 Roulette Wheel Selection(轮盘赌博选择),种群中的个体被选中的概率与个体相应的适应度函数的值成正比. \[P(h_i)=\frac{Fitness(h_i)}{\sum_{j=1}^N Fitness…

[CF913F]Strongly Connected Tournament 题意:有n个人进行如下锦标赛: 1.所有人都和所有其他的人进行一场比赛,其中标号为i的人打赢标号为j的人(i<j)的概率为$p=a\over b$.2.经过过程1后我们相当于得到了一张竞赛图,将图中所有强联通分量缩到一起,可以得到一个链,然后对每个大小>1的强联通分量重复过程1.3.当没有大小>1的强连通分量时锦标赛结束. 现在给出n,a,b,求期望比赛的场数. $n\le 2000,a<b\le 1000…