POJ 2893 M × N Puzzle

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POJ 2893 M × N Puzzle（树状数组求逆序对）

M × N Puzzle Time Limit: 4000MS Memory Limit: 131072K Total Submissions: 4112 Accepted: 1140 Description The Eight Puzzle, among other sliding-tile puzzles, is one of the famous problems…

逆序对 n 数码问题的扩展对于一个n * m 的问题来说,结论和列数 m 奇偶有关对于 m 是奇数来说 , 两个局面互相可达,当且仅当这两个局面按顺序写成一个数列,这个数列的逆序对数的奇偶性相同对于 m 是偶数来说, 两个局面互相可达,当且仅当这两个局面按顺序写成一个数列,这个数列的逆序对数的差与空格所在的行数差的奇偶性相同 (证明 ,不存在的) #include <iostream> #include <cstdio> #include <algorithm>…

POJ 2893 M × N Puzzle——八数码有解条件

题意:给定M*N的数码图,问能否移动到最终状态分析有解的判定条件可见八数码有解条件值得一提的是,这道题求逆序对卡树状数组,只能用归并排序. #include<cstdio> #include<algorithm> #include<cstring> using namespace std; ; int n,m,pos,x,ans,zero; int seq[maxn],tmp[maxn]; void msort(int l,int r) //对seq进行排序 {…

M × N Puzzle POJ - 2893（奇数码）

The Eight Puzzle, among other sliding-tile puzzles, is one of the famous problems in artificial intelligence. Along with chess, tic-tac-toe and backgammon, it has been used to study search algorithms. The Eight Puzzle can be generalized into an M × N…

【POJ】3678 Katu Puzzle

http://poj.org/problem?id=3678 题意:很幼稚的题目直接看英文题面= = #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #include <iostream> using namespace std; const int N=1000*2+10, M=N*N*4; struct E { int next, to; }…

POJ 2983 M × N Puzzle

M × N Puzzle Time Limit: 4000MS Memory Limit: 131072K Total Submissions: 4860 Accepted: 1321 Description The Eight Puzzle, among other sliding-tile puzzles, is one of the famous problems in artificial intelligence. Along with chess, tic-tac-toe a…

POJ 1651：Multiplication Puzzle（区间DP）

http://poj.org/problem?id=1651 题意:给出n个数字,每取中间一个数,就会使得权值加上中间这个数和两边的乘积,求取剩两个数最少的权值是多少. 思路:区间dp. 一开始想了挺久还是写不出方程,做了点别的事回来再想就突然觉得很简单了. 一开始使得长度为1和2的区间dp[i][j]为0. 然后dp[i][j] = min(dp[i][k] + dp[k][j] + w[k] * w[i] * w[j]). 枚举的k为中间拿掉的数,然后和左右的区间和相加就是最后答案了. #i…