http://poj.org/problem?id=1163 The Triangle Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 32923 Accepted: 19514 Description 73 88 1 02 7 4 44 5 2 6 5 (Figure 1) Figure 1 shows a number triangle. Write a program that calculates the hi…
Cow Bowling Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 13016 Accepted: 8598 Description The cows don't use actual bowling balls when they go bowling. They each take a number (in the range 0..99), though, and line up in a standard…
1.链接地址: http://bailian.openjudge.cn/practice/1163 http://poj.org/problem?id=1163 2.题目: 总时间限制: 1000ms 内存限制: 65536kB 描述 73 88 1 02 7 4 44 5 2 6 5 (Figure 1) Figure 1 shows a number triangle. Write a program that calculates the highest sum of numbers pa…
The Triangle Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 49955 Accepted: 30177 Description 73 88 1 02 7 4 44 5 2 6 5 (Figure 1) Figure 1 shows a number triangle. Write a program that calculates the highest sum of numbers passed on…
题目链接:http://poj.org/problem?id=3176 思路分析:基本的DP题目:将每个节点视为一个状态,记为B[i][j], 状态转移方程为 B[i][j] = A[i][j] + Max( B[i+1][j], B[i+1][j+1] ); 代码如下: #include <stdio.h> + ; int A[MAX_N][MAX_N], B[MAX_N][MAX_N]; int Max( int a, int b ) { return a > b ? a : b;…
看题传送门门:http://poj.org/problem?id=1163 困死了....QAQ 普通做法,从下往上,可得状态转移方程为: dp[i][j]= a[i][j] + max (dp[i+1][j] , dp[i+1][j+1] ); #include<cstdio> #include<cstring> int a[101][101]; int dp[101][101]; int main() { int n; while(~scanf("%d",…
Description The cows don't use actual bowling balls when they go bowling. They each take a number (in the range 0..99), though, and line up in a standard bowling-pin-like triangle like this: Then the other cows traverse the triangle starting from its…
动态规划:多阶段决策问题,每步求解的问题是后面阶段问题求解的子问题,每步决策将依赖于以前步骤的决策结果.(可以用于组合优化问题) 优化原则:一个最优决策序列的任何子序列本身一定是相当于子序列初始和结束状态的最优决策序列. 只有满足优化原则的问题才可以利用动态算法进行求解,因为只有全局最优解法等于其每个子问题的最优才可以分阶段进行求解. The cows don't use actual bowling balls when they go bowling. They each take a nu…